Answer:
a
b

Step-by-step explanation:
From the question we are told that
The probability that an employees suffered lost-time accidents last year is 
The probability that an employees suffered lost-time accident during the current year is

The probability that an employee will suffer lost time during the current year given that the employee suffered lost time last year is

Generally the probability that an employee will experience lost time in both year is mathematically represented as

=> 
=> 
Generally the percentage of employees that will experience lost time in both year is mathematically represented as

=> 
=>
Generally the probability that an employee will experience at least one lost time accident over the two-year period is mathematically represented as

=> 
=> 
Generally the percentage of the employees who will suffer at least one lost-time accident over the two-year period is mathematically represented as

=> 
=> 
Material=wall+2*side and material is 40 ft so:
40=w+2s
w=40-2s
Area=ws, using w from above we get:
A=(40-2s)s
A=40s-2s^2
dA/ds=40-4s and d2A/ds2=-4
Since d2A/ds2 is a constant negative acceleration, when dA/ds=0, A(s) is at an absolute maximum.
dA/ds=0 when 4s=40, s=10 ft
And since w=40-2s, w=20 ft
So the dimensions of the pen are 20 ft by 10 ft, with the 20 ft side being opposite the wall. And the maximum possible area is thus 200 ft^2
180 mins to walk 12 miles :)
Answer:
5x^2-6x-10
Step-by-step explanation:
(2x^2-2x)-(-3x^2+4x+10)
2x^2-2x+3x^2-4x-10
5x^2-2x-4x-10
5x^2-6x-10