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Varvara68 [4.7K]
3 years ago
7

What is the range of the relation

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
3 0
The answer is B sisbbbshs
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A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 6%
Georgia [21]

Answer:

a

\% E =  0.9 \%

b

\%E_1 = 10.1 \%

Step-by-step explanation:

From the question we are told that

The probability that an employees suffered lost-time accidents last year is P(e) =  0.06

The probability that an employees suffered lost-time accident during the current year is

P(c) =  0.05

The probability that an employee will suffer lost time during the current year given that the employee suffered lost time last year is

P(c | e) =  0.15

Generally the probability that an employee will experience lost time in both year is mathematically represented as

P(c \ n \ e) =  P(e) *  P(c \ |\ e)

=> P(c \ n \ e) =  0.06*   0.15

=> P(c \ n \ e) = 0.009

Generally the percentage of employees that will experience lost time in both year is mathematically represented as

\% E =  P(e \ n \ c ) * 100

=> \% E =  0.009 * 100

=> \% E =  0.9 \%

Generally the probability that an employee will experience at least one lost time accident over the two-year period is mathematically represented as

P(e \ u \ c) =  P(e) + P(c) - P(e \ n \  c)

=> P(e \ u \ c) =  0.06 + 0.05 - 0.009

=> P(e \ u \ c) =  0.101

Generally the percentage of the employees who will suffer at least one lost-time accident over the two-year period is mathematically represented as

\%E_1 = P(e \ u \ c) *  100

=> \%E_1 = 0.101*  100

=> \%E_1 = 10.1 \%

7 0
3 years ago
Joe will build a rectangular pen for his dog. A wall will form one side of the pen. Joe has 40 ft of fencing to form the other t
Svetlanka [38]
Material=wall+2*side and material is 40 ft so:

40=w+2s

w=40-2s

Area=ws, using w from above we get:

A=(40-2s)s

A=40s-2s^2

dA/ds=40-4s and d2A/ds2=-4

Since d2A/ds2 is a constant negative acceleration, when dA/ds=0, A(s) is at an absolute maximum.

dA/ds=0 when 4s=40, s=10 ft

And since w=40-2s, w=20 ft

So the dimensions of the pen are 20 ft by 10 ft, with the 20 ft side being opposite the wall.  And the maximum possible area is thus 200 ft^2
6 0
3 years ago
Read 2 more answers
If anyone understands can you please help me✨‍♀️
sergiy2304 [10]
180 mins to walk 12 miles :)
4 0
3 years ago
Mmilinu<br>Subtract - 3x2 + 4x + 10 from 2x2 – 2x​
ale4655 [162]

Answer:

5x^2-6x-10

Step-by-step explanation:

(2x^2-2x)-(-3x^2+4x+10)

2x^2-2x+3x^2-4x-10

5x^2-2x-4x-10

5x^2-6x-10

5 0
3 years ago
What is 1 2/3 minus -5 2/3 as a fraction
Sati [7]
7 1/3 hope this helps!
7 0
3 years ago
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