Answer:
x = 10
Step-by-step explanation:
OA = OD ( both radii of the circle )
OD = OB + BD = x + 16
OB is at right angles to OB ( line from centre to midpoint of chord is right )
Using Pythagoras' identity in right triangle ABO
OA² = OB² + AB² , that is
(x + 16)² = x² + 24²
x² + 32x + 256 = x² + 576 ( subtract x² from both sides )
32x + 256 = 576 ( subtract 256 from both sides )
32x = 320 ( divide both sides by 32 )
x = 10
A.2 but it could also be 4 but its not one of the answers...
Answer:
see below
Step-by-step explanation:
1) 6(x + 1)+ 5 = 35
Distribute
6x+6 +5 = 35
Combine like terms
6x+11 =35
Subtract 11
6x+11-11=35-11
6x = 24
Divide by 6
6x/6 =24/6
x = 4
2) 0.7(x - 2) = 0.3
Distribute
.7x -1.4 = .3
Add 1.4 to each side
.7x-1.4+1.4 = .3+1.4
.7x = 1.7
Divide each side by .7
.7x/.7 = 1.7/.7
x = 17/7 = 2.482571429
3) 7(4x + 9) - 13 = 87
Distribute
28x +63 -13 = 87
Combine like terms
28x +50 = 87
Subtract 50 from each side
28x +50-50 =87-50
28x=37
Divide each side by 28
28x/28 = 37/28
x = 37/28 = 1 9/28
4) 0.25(3 - x) = 0.375
Distribute
.75 -.25x = .375
Subtract .75 from each side
.75-.75 -.25x = .375-.75
-.25x = -.375
Divide each side by -.25
-.25x/-.25 = -.375/-.25
x =1.5
