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ycow [4]
3 years ago
10

Help pls :) question is in attachment

Mathematics
1 answer:
nekit [7.7K]3 years ago
6 0

Answer:

x = 1

Step-by-step explanation:

because that's the point where the two lines intersect!

You might be interested in
Explain one way to add 3 digit numbers
Ray Of Light [21]
You can add them like this:

so if 156 + 213 + 109 was the equation then you would

first put them in order from biggest to smallest

213
156
+109
-----------

then add:

¹ ← ←
213 ↑
156 ↑
+109 ↑
---------↑ ( carry the 10 )
478 (add the ¹ )

then you get the answer 478!

hope that helps :)
4 0
3 years ago
How do you write 41.344 in word form
Semenov [28]

Answer:

forty one point three hundred and forty four

Step-by-step explanation:

4 0
3 years ago
Which of the following is a characteristic of the repeating shapes in a tessellation?A. Shapes cannot be regular polygons.B. Sha
Elden [556K]
Shapes cannot have spaces between them
7 0
3 years ago
Read 2 more answers
Graph the solution x
mixas84 [53]

Answer:

I think you need to put more info

Step-by-step explanation:


8 0
3 years ago
How to solve all of this
photoshop1234 [79]
Start circle: πd = (3.14)(19) = 59.7

Move diagonally to the circle with the radius of 6.2.

Second circle: 2πr = 2(3.14)(6.2) = 39

Move upwards to the circle with the radius of 10.5

third circle: 2πr = 2(3.14)(10.5) = 66

Move right to the circle with the diameter of 16.6

Fourth circle: πd = (3.14)(16.6) = 52.2

Move down to the circle with the diameter of 7.7

fifth circle: πd = (3.14)(7.7) = 24.2

Move down to the circle with the diameter of 50

Sixth circle: πd = (3.14)(50) = 157.1

Move left to the circle with the radius of 11.8

Seventh circle: 2πr = 2(3.14)(11.8) = 74.1

Move down to the circle with the radius of 38

Eight circle: 2πr = 2(3.14)(38) = 238.8

Move right to the circle with the diameter of 1.1

ninth circle: πd = (3.14)(1.1) = 3.5

Move right to the circle with the radius of 14.8

10th circle = 2πr = 2(3.14)(14.8) = 93

Move up to the end.

Hope this helps :) 
7 0
3 years ago
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