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Natalija [7]
3 years ago
5

This this what the tutor gave me​

Mathematics
2 answers:
Feliz [49]3 years ago
8 0
My tutor gave me stuff that looks something like this I’m trying to do it rn
bogdanovich [222]3 years ago
4 0

Answer:

wow thats a lot and looks complicated

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David wants to measure the width of a road
alexira [117]

Answer:

<u>The width of the road =  25.359 m</u>

Step-by-step explanation:

See the attached figure which represents the problem.

The length of AB = 40 m

let the width of the road w.

Construct PC perpendicular to AB, So, the measure of angle C = 90°

∠B = 60° and ∠A = 45°

Let the length of AC = x, so, the length of BC = 40-x

At ΔBCP which is a right triangle at C

tan B = opposite/adjacent = w/(40-x)

w = (40-x) * tan B  ⇒(1)

At ΔACP which is a right triangle at C

tan A = opposite/adjacent = w/x

w = x * tan A  ⇒(2)

from (1) and (2)

(40-x) * tan B = x * tan A

40 tan B - x *tan B = x tan A

40 tan B  = x tan A + x *tan B

40 tan B  = x (tan A + tan B)

x = (40 tan B)/(tan A + tan B) = (40 tan 60)/(tan 60 + tan 45) = 25.359 m

substitute at (2) with x

w = x tan A = 25.359 tan 45 = 25.359 m

<u>So, The width of the road =  25.359 m</u>

8 0
4 years ago
Pls HELP ME ‼️ <br> help help help
kumpel [21]

Answer:

c is the answer pi/9

Step-by-step explanation:so we have from 1 to 6.28

so 3.14 is there

3 is there

pi/9 is about 1/3 or less than 1 so not in between

pi squared/9 is about 9.something/9 so more than 1 over 1 and in between

7 0
3 years ago
Solve each system of equations (systems with 3 variables)
Natasha2012 [34]

Answer:

x = 2 , y = 5 , z = -1 You are correct!!!

Step-by-step explanation:

Solve the following system:

{9 x + 3 y - 4 z = 37 | (equation 1)

4 x + 3 y + 7 z = 16 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Subtract 4/9 × (equation 1) from equation 2:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+(5 y)/3 + (79 z)/9 = (-4)/9 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Multiply equation 2 by 9:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Subtract 1/9 × (equation 1) from equation 3:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x - (16 y)/3 + (76 z)/9 = (-316)/9 | (equation 3)

Multiply equation 3 by 9/4:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x - 12 y + 19 z = -79 | (equation 3)

Add 4/5 × (equation 2) to equation 3:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x+0 y+(411 z)/5 = (-411)/5 | (equation 3)

Multiply equation 3 by 5/411:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Subtract 79 × (equation 3) from equation 2:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y+0 z = 75 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Divide equation 2 by 15:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Subtract 3 × (equation 2) from equation 1:

{9 x + 0 y - 4 z = 22 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Add 4 × (equation 3) to equation 1:

{9 x+0 y+0 z = 18 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Divide equation 1 by 9:

{x+0 y+0 z = 2 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Collect results:

Answer:  {x = 2 , y = 5 , z = -1

5 0
3 years ago
Find the value of y that satisfies the equation, 8.8y - 4 = 7.7y + 7.
ehidna [41]
8.8y-4=7.7y+7 \\ 8.8y-7.7y=7+4 \\ 1.1y=11 \\ y=11/1.1 \\ y=10-> answer D
3 0
3 years ago
Read 2 more answers
Arithmetic and Geometric Sequences
Alexus [3.1K]

Answer:

Step-by-step explanation:

This is arithmetic since adding 4 to each term gets us to the next term in the sequence. That means that the common difference, d, is 4. The general arithmetic explicit formula is

a_n=a_1+d(n-1) and using the info given when a1 = 3 and d = 4:

a_n=3+4(n-1) or, if you want to make it easier to deal with:

a_n=4n-1 (I just distributed through the parenthesis and then combined like terms. As you can see, arithmetic sequences are linear).

5 0
3 years ago
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