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Gwar [14]
3 years ago
5

If the volume of a rectangular pyramid is 150 inches cubes ,what is the volume of a prism with the same demensions

Mathematics
1 answer:
Ugo [173]3 years ago
7 0

\bf \stackrel{\textit{volume of a pyramid}}{V=\cfrac{Bh}{3}}\qquad \qquad \stackrel{\textit{volume of a rectangular prism}}{V=Bh}\qquad \begin{cases} B=base~area\\ h=height \end{cases}


so let's notice, the volume of the rectangular prism is really 3 times as much of that of a pyramid with the same Base and Height.

so if the pyramid has a volume of 150, the prism will have volume of 3*150.

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⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden
fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

        P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } ~ N(0,1)

where, \hat p = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = \frac{354}{1219}

           n = sample of US adults  = 1291

           p = population proportion of adults

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                                    significance level are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ]

                         = [ \frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} } , \frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} } ]

                         = [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0
3 years ago
5.1.2 Exam: Semester 2 Exam
Nikolay [14]

Answer:

See attached picture to view the graph

Step-by-step explanation:

Start by analyzing how this average idea works:

If only one member goes to the trip, it will cost him/her $1000+$200 = $1200.

If two members go to the trip, then they will share the cost as per the following: ($1000+ $200 + $200 = $1400) which they will be dividing into two people, thus costing each of them $700.

Notice that the general function that represents such average will be given by: f(x) = \frac{1000+200x}{x}

Plot such function in the two dimensional plane, and you will get the asymptotic behavior shown in the attached image.

8 0
3 years ago
At a fabric store, metallic ribbon costs $16 for 4 ft. White ribbon is priced at 3 ft per dollar. Use rates to show which kind o
Elis [28]

Metallic ribbon: 16$ for 4ft

Dividing both sides by four, we get:

1 feet -- 4 dollars

White ribbon 3$ for 1 feet

1 feet -- 3 dollars

<h2><u><em>Therefore, the Metallic ribbon costs more per feet.</em></u></h2>
4 0
2 years ago
Solve x2 - 8x = 3 by completing the square. Which is the solution set
Simora [160]

Answer:

4\pm\sqrt{19}

Step-by-step explanation:

Move everything to left side

x^{2} -8x -3 =0

Now to solve this square equation we need to find Descriminant

D=b^{2} -4ac=64+12=76

As Descriminant D is greater than 0 then we have 2 solutions which we can calculate by this formula

x_{1,2}=\frac{-b\pm\sqrt{D}}{2a} =\frac{8\pm2\sqrt{19}}{2}=4\pm\sqrt{19}

3 0
3 years ago
A van and a bicycle move towards each other. The speed of the van is 80 km per hour, and the speed of the bike is 20 km per hour
otez555 [7]

:

.

-- :

Bike > ________300km_________< Van

20km/h 80km/h

In one hour, the bike will have moved 20km and the van would have moved 80km.

The distance between them was 300km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.

300km-(20km+80km) = 200km

So now the distance between them is 200km.

Now another hour passes. The distance between them was 200km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.

200km-(20km+80km) = 100km

So now the distance between them is 100km

Now another hour passes. The distance between them was 100km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.

100km-(20km+80km) = 0km

So now the distance between them is 0km, which means they have met. If we count, it took them 3 hours.

:

Step 1)

Add both speeds. 20km+80km=100km

Step 2)

Total distance between them = 300km

So do 300km/100km = 3hours.

______

The solution is: .

————

Hope this helped!

4 0
3 years ago
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