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2 years ago

What is the equation of the line that passes through the point (7,-3) and has an undefined slope?

Mathematics

1 answer:

Vika [28.1K]2 years ago

7 0

Answer:

X = 7

Step-by-step explanation:

Any line with a undefined slope is a vertical line, which goes up and down.

Since this is a vertical line, and our x-value is 7, this means that the vertical line has the x-coordinate 7 at all times, making the equation x = 7.

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Slope of (27,2),(38,-15)

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The measures of two complementary angles have a ratio of 3:2 what is the meusure of the larger angle

ozzi

Answer:

Step-by-step explanation:

The two angles add to 90 degrees since they are complementary

the ratio is 3:2

Multiply by x

3x:2x

Add them together and set equal to 90

3x+2x=90

5x=90

Divide each side by 5

5x/5 = 90/5

x = 18

The first angle is 3*18 = 54

The second angle is 2*18 = 36

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3 years ago

Choose the letter that you think best answers the question.

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Answer: 1)

a combination

b permutation

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B coz 6 and 11 is the only combination which can have 462 possibilities as they r both factors of 462

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3 years ago

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3 years ago

A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe

adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

$\frac{dC}{dt}=Ci*Qi-Co*Qo$

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

$\frac{dC}{dt}=-Co*Qo$

Rearranging the equation, it becomes

$\frac{dC}{C}=-Qo*dt$

Integrating both sides

$\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}$

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

$C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\$

The final equation for the concentration of salt at any given time is

$C=exp^{-3*t-0.693}$

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

$C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}= -\frac{-0.266}{3}=0.088$

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3 years ago