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dmitriy555 [2]
3 years ago
15

The lengths of the sides of a triangle are in the extended ratio 44 ​: 55 ​: 77. the perimeter of the triangle is 6464 cm. what

are the lengths of the​ sides?
Mathematics
1 answer:
joja [24]3 years ago
6 0
44x + 55x + 77x = 6,464 centimeters.
x = <span> <span> <span> 36.7272727273 </span>

Therefore the sides are
44*</span></span><span><span>36.7272727273 = 1,616 </span>
55*</span><span>36.7272727273  </span>= 2,020
77* <span> <span> <span> 36.7272727273 </span> </span> </span> = 2,828

OR maybe that's another of those infamous Brainly typos.

4x + 5x + 7x = 64 centimeters.
x = 8

Therefore the sides are
4*8 = 32
5*8 = 40 and
7*8 = 56 centimeters



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slavikrds [6]

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The wind force f on a sail varies jointly as the area a of the sail and the square of the wind speed w.
blondinia [14]

Answer:

  122.5 lbs

Step-by-step explanation:

The relation between force, wind speed, and area can be written ...

  f = ks²a

for some wind speed s and area a.

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The constant of proportionality, k, can be found from the given data.

  64.8 = k(18²)(500) . . . force in pounds, area in square feet, speed in mph

  k = 64.8/(324×500) = 0.0004

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Using the equation with the second set of data, we have ...

  f = 0.0004(35²)(250) = 122.5 . . . . pounds

The force on the 250 square foot sail would be 122.5 pounds.

4 0
2 years ago
PLS HELP ME ASAP!!! THANKS!!
MariettaO [177]
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5 0
3 years ago
A major credit card company has determined that customers charge between $100 and $1100 per month. If the monthly amount charged
Alexxx [7]

Answer:

a) E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600

b) First we need to calculate the variance given by this formula:

Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33

And the deviation would be:

Sd(X) = \sqrt{83333.33}= 288.675

c) P(600 < X< 889) = P(X

And using the cdf we got:

P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289

d) P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578

Step-by-step explanation:

For this case we define the random variable X who represent the customers charge, and the distribution for X on this case is:

X \sim Unif (a= 100,  b=1100)

Part a

For this case the average is given by the expected value and we can use the following formula:

E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600

Part b

First we need to calculate the variance given by this formula:

Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33

And the deviation would be:

Sd(X) = \sqrt{83333.33}= 288.675

Part c

For this case we want to find the percent between 600 and 889, so we can use the cumulative distribution function given by:

F(x) = \frac{X -100}{1100-100}= \frac{x-100}{1000}, 100 \leq X \leq 1100

And we can find this probability:

P(600 < X< 889) = P(X

And using the cdf we got:

P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289

Part d

P(311 < X< 889) = P(X

And using the cdf we got:

P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578

6 0
3 years ago
A jar contains n nickels and d dimes. There is a total of 236 coins in the jar. The value of the coins is $15.75. How many nicke
just olya [345]

The total if all 236 coins were nickels would be $11.80, which is $3.95 short of the actual amount.

Replacing a nickel with a dime adds $0.05 to the total value, so there must have been $3.95/$0.05 = 79 such replacements.

There are 79 dimes.

There are 236 -79 = 157 nickels.

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Solving the first for n, we get

... n = 236 - d

Substituting that into the second equation, we have

... .05(236 -d) +.10d = 15.75

... .05d = 15.75 -236·.05 . . . . . collect terms, subtract .05·236

... d = 3.95/.05 . . . . . . . . . . . . . divide by .05

... d = 79

... n = 236-79 = 157

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The solution should look familiar, as it matches the verbal description at the beginning.

6 0
4 years ago
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