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KonstantinChe [14]
3 years ago
13

Use the box and whisker plot to answer the question what is the minimum value

Mathematics
2 answers:
Elenna [48]3 years ago
7 0
300

The minimum value is the lowest number that is graphed.

Since every value is going up/ down 100 you can say that 300 is the lowest value.
ycow [4]3 years ago
6 0
300 is the answer. The number line counts in increments of 100 per line.
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Samantha works at a nursery where she pots plants. It takes her 1 1/2 hours to pot 12 plants. How many plants can Samantha pot i
ahrayia [7]
She can plot 9 in 1 hour
3 0
3 years ago
Evaluate the expression: v ? w Given the vectors: r = <8, 1, -6>; v = <6, 7, -3>; w = <-7, 5, 2> . If the answ
Snezhnost [94]

Answer:

-13

Step-by-step explanation:

Given are two vectors v and w.

v=(6,7,-3) and

w=(-7,5,2)

We are to find the dot product of v.w

We have

Dot product is obtained by multiplying corresponding pairs and adding them

Here we have

v.w=6(-7)+7(5)-3(2)

=-13

7 0
3 years ago
Find the two points on segment AB that divide the segment into 3 congruent Parts if A has coordinates (0 0) and point B has coor
Elena L [17]

Answer:

  (3, 2), (6, 4)

Step-by-step explanation:

Since one end (A) of the segment AB is at the origin, the required points will be 1/3 and 2/3 of the coordinates of B:

  (1/3)(9, 6) = (3, 2)

  (2/3)(9, 6) = (6, 4)

8 0
3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
Which of the following graphs would you use if you wanted viewers to see individual data points?
Arturiano [62]
I would either use a histogram or a frequency chart, but histogram is easier and neater 
7 0
3 years ago
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