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KatRina [158]
3 years ago
10

Select the two binomials that are factors of 81x2 -36

Mathematics
1 answer:
grigory [225]3 years ago
6 0

Answer:

81, and 2

Step-by-step explanation:

Binomials are the two parts of a equation in this case 81 times 2  -36, 81 and 2 would be the binomials because they're the first two parts of the equation.

Other examples:

x - y

x \times y

x + y

x \div y

Hope this helps.

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Find e^cos(2+3i) as a complex number expressed in Cartesian form.
ozzi

Answer:

The complex number e^{\cos(2+31)} = \exp(\cos(2+3i)) has Cartesian form

\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2).

Step-by-step explanation:

First, we need to recall the definition of \cos z when z is a complex number:

\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}.

Then,

\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}. (I)

Now, recall the definition of the complex exponential:

e^{z}=e^{x+iy} = e^x(\cos y +i\sin y).

So,

e^{2i-3} = e^{-3}(\cos 2+i\sin 2)

e^{-2i+3} = e^{3}(\cos 2-i\sin 2) (we use that \sin(-y)=-\sin y).

Thus,

e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)

Now we group conveniently in the above expression:

e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2.

Now, substituting this equality in (I) we get

\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2.

Thus,

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right].

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3 years ago
What is the value of the function f(x) = 1.5x + 7.6 when x = 1.1?
dangina [55]
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</span><span>f(1.1) = 1.5(1.1) + 7.6
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Country Financial, a financial services company, uses surveys of adults age and older to determine if personal financial fitness
lesya692 [45]

Complete question :

Country Financial, a financial services company, uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time (USA Today, April 4, 2012). In February of 2012, a sample of 1000 adults showed 410 indicating that their financial security was more than fair. In February of 2010, a sample of 900 adults showed 315 indicating that their financial security was more than fair. a. State the hypotheses that can be used to test for a significant difference between the population proportions for the two years. H : Pi - P2 - Select your answer HA : P1 P2 - Select your answer - b. What is the sample proportion indicating that their financial security was more than fair in 2012? Round your answer to two decimal places. In 2010?

Answer:

H0 : p1 - p2 = 0

H1 : p1 - p2 ≠ 0

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Step-by-step explanation:

The null and alternative hypothesis :

H0 : p1 - p2 = 0

H1 : p1 - p2 ≠ 0

The null means there is no difference in proportion for the two years while the alternative claims that there is difference in proportion for the two years.

Sample proportion for 2010:

Phat = x / n

x = 315 ; n = 900

Phat = 315 / 900

Phat = 0.35

Sample proportion for 2012 :

Phat = x / n

x = 410 ; n = 1000

Phat = 410 / 1000

Phat = 0.41

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3 years ago
Please answer quickly, thanks <br> -2 + ?? = -12
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Answer:

-10

Step-by-step explanation:

-2 + ? = -12

+2          +2

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