PLEASE SOMEONE GOOD WITH MATH HELP! With work plz!! Will award brainliest!!

What is 5,403.264 rounded to the nearest hundred

Likurg_2 [28]

The answer is 5400.000. Hope this helps.

6 0

2 years ago

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What is the distance between points A and B?

galina1969 [7]

-4,-3,-2,-1,0
which means 4 numbers

5 0

2 years ago

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Why wont anybody help me i posted like 5 questons but heres the question :(

melamori03 [73]

Answer:

i got you fam

Step-by-step explanation:

its b fam because the top x value goes by 1 then 2 and the y value goes from 2 to 4

6 0

2 years ago

The points (–5, 6) and (5, 6) are vertices of a hexagon. The line segment joining the two points forms one of the sides of the h

xxTIMURxx [149]

The information about the points being vertices that make up a line to represent the side of a hexagon is irrelevant, as we are only looking for the distance of a line based on their x and y coordinates.

Look at the point's x and y coordinates:

First point:

x = -5, y = 6

Second point:

x = 5, y = 6

You'll notice that the y-coordinate for both points is the same (6 = 6). This means that the segment created by the points will be horizontal, since there is only movement on the x-axis if you trace the segment from point to point.

To find the distance between the two points, we'll only need to subtract the first point's x-coordinate from the second:

5 - (-5) = 5 + 5 = 10

The answer will be the following statement:

Since the y-coordinates are the same, the segment is horizontal, and the distance between the points is 10 units.

5 0

3 years ago

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GJ is a midsegment of triangle DEF, and HK is a midsegment of triangle GFJ. What is the length of HK?

loris [4]

Answer:

Option B) 4 centimeters

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the value of n

we know that

a) GJ is a midsegment of triangle DEF

then

G is the midpoint segment DF and J is the midpoint segment EF

DG=GF and EJ=JF

b) HK is a midsegment of triangle GFJ

then

H is the midpoint segment GF and K is the midpoint segment JF

GH=HF and JK=KF

In this problem we have

HF=7 cm

so

GH=7 cm

GF=GH+HF ----> by addition segment postulate

GF=7+7=14 cm

Remember that

DG=GF

substitute the given values

$2n-1=14$

solve for n

$2n=14+1$

$2n=15$

$n=7.5\ cm$

step 2

Find the length of GJ

we know that

The <u><em>Midpoint Theorem</em></u> states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side

so

$GJ=\frac{1}{2}DE$