Answer:
(7,3)
Step-by-step explanation:
Given,7 units away from x axis and 3 units away from y axis,
Coordinates are written in (x,y) form
(x,y)=(7,3)(Given)
Given a right angle triangle
The length of the legs are 4 and 7
we will find the hypotenuse using the Pythagorean theorem
So,
![\begin{gathered} h^2=7^2+4^2=49+16=65 \\ h=\sqrt[]{65}\approx8.062 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D7%5E2%2B4%5E2%3D49%2B16%3D65%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B65%7D%5Capprox8.062%20%5Cend%7Bgathered%7D)
Rounding to the nearest tenth
So, the answer is the length of the third side = 8.1
Ur mom and a buttcheek on a stick
The winning probability is 1/3.
<h3>
What is probability?</h3>
- A probability is a number that represents the likelihood or chance that a specific event will occur.
- Probabilities can be stated as proportions ranging from 0 to 1, as well as percentages ranging from 0% to 100%.
To find the winning probability:
- Favorable outcomes to win are 3 and 6.
- Total outcomes are 6in fair dice.
- To win $20 × 3 or $20 × 6 favorable outcome is 1 (3 and 6 respectively).
- The probability is 1 / 6.
- So, the probability of winning some money = 2/6 = 1/3
Therefore, the winning probability is 1/3.
Know more about probability here:
brainly.com/question/24756209
#SPJ4
The statement that correctly describes the horizontal asymptote of g(x) is:
Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.
<h3>What are the asymptotes of a function f(x)?</h3>
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, the function is:

The horizontal asymptote is given as follows:

Hence the correct statement is:
Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.
More can be learned about asymptotes at brainly.com/question/16948935
#SPJ1