Answer: The problem that we would expect this mouse to have is a tendency to DRINK MORE WATER THAN NORMAL accompanied by EXCRETION OF DILUTE URINE
Explanation:
The right answer is 202.5 - 292.5 grams of carbohydrates a day.
The man's caloric requirements are around 2500 calories / day. So the subject tries to create a calorie deficit.
1 gram of carbohydrate equals 4 calories.
45% - 65% of the calorie intake (1800kcal) corresponds to 0.810 - 1.170 Kcal. (810 and 1170 calories).
So:
4 calories ==> 1 gram of carbohydrates
810 calories ==> 810/4 = 202.5 grams of carbohydrates
1170 calories ==> 1170/4 = 292.5 grams of carbohydrates.
So, the subject must consume between 202.5 and 292.5 grams of carbohydrates a day.
The answer would be chromosomes
Answer: is C). <u><em>Coral reef organisms carry out photosynthesis using the sunlight that passes through the clear water above</em></u>.
Explanation:
In ecosystem, an abiotic factor is any non-living factor that influences the biotic factors and the population. Following are the examples of abiotic factors namely, atmosphere, chemical elements, sunlight, wind, water. some are also given below:
- sunlight
- oxygen
- nitrogen
- climate
- temperature
- pH and Water
Option C: is the only right option as it falls under the criteria of relationship between abiotics and biotc factors. Here abiotic factor is sinlight and abiotic factor is coral leaf. All other options are related to biotic factors (living things that shape an ecosystem). Examples of biotic factors are animals, plants, bacteria and fungi
Option A: description of predator and it's prey (biotic factor)
Option B: Also relationship between two living things i.e. squirrels and bird's eggs (biotic factor)
Option D: Comparison between two plants (biotic factor)
The allele frequency for the recessive allele is B. 0.10. Thus, option "B" is correct.
<h3>How, explain your answer?</h3>
The Hardy-Weinburg equation is p + q = 1, or p^2 + 2pq + q^2 = 1, where p is dominant and q is recessive.
If 10 out of 100 rabbits have white fur, 10% of the rabbits have white fur. Therefore, 90% of the rabbits have brown fur, which can be substituted into the first equation to becoming 0.9 + 0.1 = 1. Now that we know what p and q equal, we can solve the rest of the equation.
0.9^2 = 0.81
0.9 * 0.1 * 2 = 0.18
0.1^2 = 0.01
Therefore, the allele frequency of the recessive allele is 0.1.
To learn more about Hardy-Weinberg equation click here:
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