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IRISSAK [1]
3 years ago
10

Which celestial body would have the strongest gravitational pull on a satellite orbiting 100 km above its surface? Explain your

answer
Biology
2 answers:
Fudgin [204]3 years ago
8 0

Answer:

Jupiter

Explanation

gravitational force depends on the mass of the body. Gravitational force is directly proportional to the the mass of body.

We know that gravitational force act on a satellite of mass m orbiting 100km above the surface is given by the following formula

F=\frac{GmM}{r^2}

Here,

G is universal gravitational constant

m-mass of satellite

M- Mass of celestial body which pull the satellite

r- distance between satellite and celestial body

Gravitational force will be maximum when M will be maximum

we know that Jupiter is the largest planet and it  has the largest mass hence Jupiter will have the strongest gravitational pull on a satellite orbiting 100 km above its surface

VARVARA [1.3K]3 years ago
3 0
Jupiter, perhaps. Other than that. Nah.
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A heterozygous round seeded plant (Rr) is crossed with a homozygous round seeded plant (RR).
igomit [66]
So I don’t see answer choices here, but your answer is 50% of the offspring will be homozygous dominant with RR, and 100% of them will carry a homozygous dominant gene of Rr

If you take the two sets and put them into a punnett square, it would look like this (image attached):

When the two sets of alleles are crossed, you would end up with half of your pairs being fully dominant (RR), and the other half being dominant while containing a recessive gene (Rr). Since there’s only one recessive gene in these pairs, it gets overridden and the pair itself is dominant.

So your answer is 50% will be homozygous dominant with RR!

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A grandfather has an x-linked disease. His wife does not have the disease and she is not a carrier for it. What is the probabili
kotykmax [81]

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A fertilizer producer finds that it can sell its product at a price of dollars per unit when it produces units of fertilizer. Th
Vilka [71]

Answer:

700

Explanation:

If from the question the price per unit of fertilizer, p(x) = 300 - 0.1x

The cost of x units of  fertilizer = C(x) = 15000 + 125x + 0.025x^2

And we know that Profit = Revenue - Cost

Revenue for x units of fertilizer R(X) = x*p(x)

= 300x - 0.1x^2

Hence Profit: P(x) = R(x) - C(x)

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