What is the answer for this math question

James has a total of 66 dollars in his piggy bank. He only has one dollar bills and two dollar bills in his piggy bank. If there

Dima020 [189]

Answer: 17

Step-by-step explanation: 66 - 49 = 17

3 0

4 years ago

Solve. 3 + |t + 4| < 10

vivado [14]

3 + |t + 4| < 10

Subtract 3

|t + 4| < 7

Because it is absolute value...

t + 4 < 7 AND t + 4 > -7

t < 3 AND t > -11

ANSWER:

t < 3 AND t > -11

8 0

3 years ago

Read 2 more answers

Find the difference and reduce to the lowest terms 12 4/9 - 8 5/6 =

butalik [34]

Answer: $3\frac{11}{18}$

Turn 12 4/9 into an Improper Fraction

Multiply $12*9$ and get $108$ . Now add $4$ and get $112$ .

$12\frac{4}{9} =\frac{112}{9}$

Turn 8 5/6 into an Improper Fraction

Multiply $8*6$ and get $48$ . Now add $5$ and get $53$ .

$8\frac{5}{6} =53/6$

Find Common Denominator

$9: 9,18,27,36,45\\6: 6,12,18,24,30\\\CD=18$

Your new problem: $\frac{112}{18}-\frac{53}{18}$

Subtract

$\frac{112}{18}-\frac{53}{18}=\frac{65}{18}$

Simplify

$\frac{65}{18} =3\frac{11}{18}$

6 0

4 years ago

Read 2 more answers

Hat is the value of x in the equation 3 x minus 4 y equals 65, when y equals 4?

kobusy [5.1K]

Answer:

16.3 repeating

Step-by-step explanation:

3x-4(4)=65

3x-16=65

3x=65-16

3x=49

x=49/3

x=16.3 repeating

8 0

3 years ago

It is known that IQ scores form a normal distribution with a mean of 100 and a standard deviation of 15. If a researcher obtains

sdas [7]

Answer:

$X \sim N(100,15)$

Where $\mu=100$ and $\sigma=15$

We select a sample of n=16 and we are interested on the distribution of $\bar X$ , since the distribution for X is normal then we can conclude that the distribution for $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Because by definition:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$E(\bar X) = \mu$

$Var(\bar X) = \frac{\sigma^2}{n}$

And for this case we have this:

$\mu_{\bar X}= \mu = 100$

$\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(100,15)$

Where $\mu=100$ and $\sigma=15$

We select a sample of n=16 and we are interested on the distribution of $\bar X$ , since the distribution for X is normal then we can conclude that the distribution for $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Because by definition:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$E(\bar X) = \mu$

$Var(\bar X) = \frac{\sigma^2}{n}$

And for this case we have this:

$\mu_{\bar X}= \mu = 100$

$\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75$

6 0

3 years ago