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blagie [28]
3 years ago
5

What is a spin quantum number?

Chemistry
2 answers:
Marta_Voda [28]3 years ago
8 0
It is a value (of 1/2) that describes the angular momentum of an electron in either clockwise or in anti-clockwise direction..........
sveta [45]3 years ago
8 0
Is a quantum number the parameterizes the intrinsic angular momentum of any given particle.
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How many grams of calcium phosphate are theoretically produced if we start with 3.40 moles of calcium nitrate and 2.40 moles of
rosijanka [135]

The theoretical yield of Ca₃(PO₄)₂ is 372 g.

<h3>Calculation:</h3>

It is based on limiting reactants. The limiting reactant is the one that yields the fewest moles in the final product. The reaction ends when it runs out.

A balanced equation is given as:

3Ca(NO₃)₂ + 2Li₃PO₄ → 6LiNO₃ + Ca₃(PO₄)₂

Multiply the moles of each reactant by the mole ratio between it and Ca₃(PO₄)₂ in the balanced equation, so that the moles of the reactant cancel, leaving moles of Ca₃(PO₄)₂.

3.40 mol Ca(NO₃)₂ × 1 mol Ca₃(PO₄)₂/3 mol Ca(NO₃)₂ = 1.13 mol Ca₃(PO₄)₂

2.40 mol Li3PO4 × 1 mol Ca₃(PO₄)₂/2 mol Li₃PO₄ = 1.20 mol Ca₃(PO₄)₂

Ca(NO₃)₂ is the limiting reactant.

Now, calculate the mass of 1.20 mol Ca₃(PO₄)₂.

Molar mass Ca₃(PO₄)₂ = 310.174 g/mol

1 mol Ca₃(PO₄)₂ = 310.174 g/mol

1.20 mol Ca₃(PO₄)₂ = 1.20 mol × 310.174 g/mol

                                = 372 g

Hence, the theoretical yield of Ca₃(PO₄)₂ is 372 g.

Learn more about limiting reactants here:

brainly.com/question/28170241

#SPJ4

3 0
2 years ago
Urea, (NH2)2CO, is a product of metabolism of proteins. An aqueous solution is 37.2% urea by mass and has a density of 1.032 g/m
Feliz [49]

Answer:

The molarity of urea in this solution is 6.39 M.

Explanation:

Molarity (M) is <em>the number of moles of solute in 1 L of solution</em>;  that is

molarity = moles of solute ÷ liters of solution

To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.

Our first step is to calculate the moles of urea in 100 grams of the solution,

using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is

60.06 g/mol ÷ 37.2 g = 0.619 mol

Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.

1.032 g/mL ÷ 100 g = 96.9 mL

This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.

0.619 mol/96.9 mL × 1000 mL= 6.39 M

Therefore, the molarity of the solution is 6.39 M.

4 0
4 years ago
A chemical engineer is studying the two reactions shown in the table below.
Kamila [148]

Explanation:

Here are the answers. Do note that I had to convert the enthalpy to joules and temperature to Kelvin to make the unit for entropy work out.

4 0
3 years ago
Glucose is the sole energy source, what fraction of the carbon dioxide exhaled by animals is generated by the reactions of the c
olganol [36]
2/3 is the fraction of the carbon dioxide exhaled by all of the animals that is generated by the reactions of the citric acid cycle, if the gluscose is the sole energy source. So if the glucose is the energy source the fraction of the carbon dioxide is 2/3. The answer in this question is 2/3
3 0
3 years ago
Someone please help me
Vladimir79 [104]

Answer:reflection

Explanation:

6 0
3 years ago
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