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4 years ago

According to the collision theory, what happens in a collision without sufficient energy or correct orientation

Chemistry

2 answers:

Sergeeva-Olga [200]4 years ago

7 0

There won't be a substantial change or effect if the collision does not meet the requirement. Hope this helps!

ohaa [14]4 years ago

3 0

Hi!

In collision theory, for a chemical reaction to occur - there must be sufficient energy to break down chemical bonds.

We call this the activation energy, as it's the energy needed to activate a chemical reaction!

Hopefully, this helps! =)

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If 1/4 cups are in 1 serving jow many servings are in 4 cups

mote1985 [20]

Answer:

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Explanation:

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3 years ago

Write a balanced half-reaction for the product that forms at each electrode in the aqueous electrolysis of the following salts:(

likoan [24]

Balanced Half reactions are:

At anode 2 $Cl^{-}$ ==> Cl₂+ $2e^{-}$ + H₂O ==> $ClO^{-}$ + 2 $H^{+}$ + $Cl^{-}$

At Cathode: 2 $H^{+}$ + $2e^{-}$ ==> H₂

Since the question states that you are using an aqueous solution of MnCl₂, so ions will have present are, H₂O, $H^{+}$ , $Mn^{2+}$ and $Cl^{-}$

Now at Anode reaction will occur as given:

2 $Cl^{-}$ ==> Cl₂+ $2e^{-}$ + H₂O ==> $ClO^{-}$ + 2 $H^{+}$ + $Cl^{-}$ (will occur)

At Cathode:

2 $H^{+}$ + $2e^{-}$ ==> H₂ (will occur)

At Cathode:

$Mn^{2+}$ + $2e^{-}$ ==> Mn (This reaction will not occur)

The deposition of solid Mn will not occur because in aqueous solution, $H^{+}$ will be reduced before $Mn^{2+}$ .

The reduction potentials for $H^{+}$ is zero whereas reduction potential for $Mn^{2+}$ is - 1.18V.

The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.

To learn more about the half reaction please click on the link brainly.com/question/13186640

#SPJ4

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2 years ago

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Oksana_A [137]

Answer:

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3 years ago

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vovikov84 [41]

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