Hello, we need to see it as a difference of two squares as we know that for all a and b real numbers
So, here
Voila !
Thank you
Lets write the problem info into an equation and solve step by step:
7(1/3 + 4/5)
the minimum common multiple of 3 and 5 is 15, so we multiply and divide the fractions by a proper number to convert them to be divided by 15 so is easier to add them:
<span>(1/3)(5/5) = (1*5)/(3*5) = 5/15
(4/5)(3/3) = (4*3)/(5*3) = 12/15
</span>so we substitute in the original equation:
7(1/3 + 4/5<span>)
</span>= 7(5/15 + 12/15<span>)
= 7(17/15)
= (7*17)/15
= 119/15</span>
Answer:
1: -13
Step-by-step explanation:
First, simplify the equation to -2y+10=36
Subtract 10 from both sides
-2y=26
Divide negative 2 from both sides
y=-13
9514 1404 393
Answer:
0.4, 0.004, 0.004
Step-by-step explanation:
The "what" in each case is found by dividing the target value by 10. That is accomplished by moving the decimal point one place to the left.
4/10 = 0.4 ⇒ 10 times 0.4 = 4
0.04 and .04 are exactly the same value, so the last two on your list are the same:
0.04/10 = 0.004 ⇒ 10 times .004 = 0.04
<h2>
Forming Equations from Word Problems</h2>
To form equations from word problems, we can derive mathematical operations as well as variables from the given information.
In this case, each time Walker reads a certain number of pages, we subtract that from the total number of pages left to know how many pages is left to read.
<h2>Solving the Question</h2>
<em>Let r represent the pages left to read.</em>
<em />
792 pages in total
Walker reads 15 pages a day during the week and 25 pages a day during the weekend.
- There are 5 weekdays, and he reads 15 pages each of those days. ⇒ <em>r</em> = 792 - 5×15
- There are 2 weekend days, and he reads 25 pages each of those days.
⇒ <em>r</em> = 792 - (5×15 + 2×25)
5 weeks have passed
- Multiply the terms representing the number of pages he reads a week by 5, for 5 weeks.
⇒ <em>r</em> = 792 - (5×15 + 2×25)×5
<h2>Answer</h2>
<em>r</em> = 792 - (5×15 + 2×25)×5
