Answer:
4/5
Step-by-step explanation:
1+3=4
Answer:
x = 1/4
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
Answer:
2 solutions
Step-by-step explanation:
I like to use a graphing calculator to find solutions for equations like these. The two solutions are ...
__
To solve this algebraically, it is convenient to subtract 2x-7 from both sides of the equation:
3x(x -4) +5 -x -(2x -7) = 0
3x^2 -12x +5 -x -2x +7 = 0 . . . . . eliminate parentheses
3x^2 -15x +12 = 0 . . . . . . . . . . . . collect terms
3(x -1)(x -4) = 0 . . . . . . . . . . . . . . . factor
The values of x that make these factors zero are x=1 and x=4. These are the solutions to the equation. There are two solutions.
__
<em>Alternate method</em>
Once you get to the quadratic form, you can find the number of solutions without actually finding the solutions. The discriminant is ...
d = b^2 -4ac . . . . where a, b, c are the coefficients in the form ax^2+bx+c
d = (-15)^2 -4(3)(12) = 225 -144 = 81
This positive value means the equation has 2 real solutions.
Answer:
![\displaystyle Range: Set-Builder\:Notation → [y|-2 ≤ y] \\ Interval\:Notation → [-2, ∞) \\ \\ Domain: Set-Builder\:Notation → [x|-4 ≤ x] \\ Interval\:Notation → [-4, ∞)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Range%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5By%7C-2%20%E2%89%A4%20y%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-2%2C%20%E2%88%9E%29%20%5C%5C%20%5C%5C%20Domain%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bx%7C-4%20%E2%89%A4%20x%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-4%2C%20%E2%88%9E%29)
Explanation:
<em>See above graph</em>
I am joyous to assist you anytime.