Question

1. A 20 kg object is thrown with an initial upward velocity of 2 m/s. If air resists motion of the object by 4 N for each m/s, what is the terminal velocity of this object? (Hint: use the model developed in Day 10 Lecture notes)

Answer 1

Answer:

  49 m/s

Step-by-step explanation:

We don't know what your model is, so we'll solve this based on the balance of forces. Air resistance exerts an upward force of ...

  (4 N/(m/s))v

Gravity exerts a downward force of ...

  (20 kg)(9.8 m/s²) = 196 N

These are balanced (no net acceleration) when ...

  (4 N/(m/s))v = 196 N

  v = (196 N)/(4 N/(m/s)) = 49 m/s

The terminal velocity is expected to be 49 m/s.