What structure was constructed for the fair of 1889
1 answer:
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Answer:
- 20.6
Step-by-step explanation:
<u>Coordinates given:</u>
- D(-3,2)
- E(4,2)
- F(4,-3)
<u>Plotted, these points give a right triangle with hypotenuse DF</u>
- Distance DE = 4 - (-3) = 7
- Distance EF = 2 - (-3) = 5
- Distance DF = √(7²+5²) = √84 = 8.6
<u>Perimeter</u>
- P = 7 + 5 + 8.6 = 20.6
