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VladimirAG [237]
3 years ago
12

A circle has a diameter of 13 centimeters and a central angle EOG that measures 280 degrees. What is the length of the intercept

ed arc EG? Use 3.14 for pi and round your answer to the nearest tenth. A) 10.1 cm B) 15.9 cm C) 31.7 cm D) 63.5 cm
Mathematics
1 answer:
Tasya [4]3 years ago
8 0
Circumference of the circle = pi * diameter = 3.14 *  13 =  40.82

Length of EG  =  40.82 * 280 / 360  =  31.7 cm.
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3 0
4 years ago
Which expression equals 93102
Karo-lina-s [1.5K]

Answer:

you got this

Step-by-step explanation:

goodluck

4 0
3 years ago
Marquis used the steps below to find the solution to the inequality Negative 5. 6 greater-than-or-equal-to x 3. 6. Step 1 Subtra
NISA [10]

Marquis solutions are;

  • The value of x is less than or equal to -9.2.
  • Negative 9.2 is greater than or equal to x.
  • The closed circle is at -9.6 that is everything to the left of the circle is shaded.
<h3>What is inequality?</h3>

Inequality is simply a type of equation that does not have an equal sign in it. Inequality is defined as a statement about the relative size as we will as is used to compare two statements.

Marquis used the steps below to find the solution to the inequality Negative 5.6 greater than or equal to x + 3.6 that can be written as

\rm -5.6 \geq  x + 3.6

A.  Then the value of x will be

      - 5.6 ≥ x + 3.6

-5.6 - 3.6 ≥ x

       -9.2 ≥ x

B.  Negative 9.2 is greater than or equal to x.

C.  The number line is shown. The closed circle is at -9.6 that is everything to the left of the circle is shaded.

More about the inequality link is given below.

brainly.com/question/19491153

7 0
2 years ago
What are the solutions of the quadratic equation (x + 3)(x +3) = 49? Ax = -2 and x = -16 Bx = 2 and x = -10 Cx = 4 and x = -10 D
Ivahew [28]

Answer:

4 and -10

Step-by-step explanation:

\displaystyle (x + 3)(x +3) = 49 \\ x^2+3x+3x+9=49 \\ x^2 +6x+9=49 \\ x^2 + 6x + 9 - 49 = 0 \\x^2+6x-40=0 \\\\ \Delta=b^2-4ac \\ \Delta=6^2-4 \cdot 1 \cdot (-40) \\ \Delta=36+160 \\ \Delta=196 \\ \\ X_{1,2}=\frac{-b \pm \sqrt{\Delta} }{2a}  \\ \\ X_1=\frac{-b+\sqrt{\Delta} }{2a} = \frac{-6+14}{2} = \frac{8}{2}=4 \\ \\ X_2=\frac{-b-\sqrt{\Delta} }{2a}  = \frac{-6-14}{2}=\frac{-20}{2} = -10

4 0
3 years ago
Answer for a,b,and c PLEASE!!!
Mekhanik [1.2K]
A: Yes
B: .5, 1, 1.5
C: d=t/ 6 2/3 - or somthing like that
8 0
3 years ago
Read 2 more answers
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