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maw [93]
3 years ago
9

The table shows three unique functions. Which statements comparing the functions are true? Select three options. A. Only f(x) an

d h(x) have y-intercepts. B. Only f(x) and h(x) have x-intercepts. C. The minimum of h(x) is less than the other minimums. D. The range of h(x) has more values than the other ranges. E. The maximum of g(x) is greater than the other maximums.

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0

Answer:

CDE

Step-by-step explanation:

A)  Only h(x) has a y intercept which is at x=0. At this point the y intercept is 0.

B) Only f(x) have a x intercept at f(x) = 0. The graph of f(x) touches the x axis at f(x) = 0.

C) h(x) has the lowest minimum, its minimum is at -28 while f(x) have a minimum at -14 and g(x) have a minimum at 1/49

D) The range of h(x) has more values than the other ranges ranging from -28 to -28.

E) g(x) has the highest maximum, its maximum is at 49 while f(x) have a maximum at 14 and h(x) have a maximum at 0

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For this problem. it is found that:

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<h3>What is a linear function?</h3>

A linear function is modeled by:

y = ax + b

In which:

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  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

From the problem, we have that:

a) The automobile has depreciated 75% in 5 years, as 4000/14500 = 0.25, and 100% - 25% = 75%.

b) The value of the automobile was reduced by $10,500 in five years, as 14500 - 4000 = $10,500.

For the linear function, we have that:

  • The initial value is b = 14500.
  • The slope is of a = -10500/5 = -2100.

Hence the linear function is: s(t) = 14,500 - 2,100t.

More can be learned about linear functions at brainly.com/question/24808124

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Imagine a simpler problem: the bell has rung just two times since Ms. Johnson went into her office. How long has Ms. Johnson been in her office? It could be almost as short as just 15 minutes (1×15), if Ms. Johnson went into her office just before the bell rang the first time, and the bell has just rung again for the second time.

Or it could be almost as long as 45 minutes (3×15), if Ms. Johnson went into her office just after the bells rang, and then 15 minutes later the bells rang for the first time, and then 15 minutes after that the bells rang for the second time, and now it’s been 15 minutes after that.

So if the bells have run two times since Ms. Johnson went into her office, she could have been there between 15 minutes and 45 minutes. The same logic applies to the case where the bells have rung 24 times—it could have been any duration between 345 and 375 minutes since the moment we started paying attention to the bells!

Step-by-step explanation:

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