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dybincka [34]
3 years ago
8

How do I solve (fraction) 2/3d=1/6?

Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0

Answer:

  d = 1/4

Step-by-step explanation:

Multiply the equation by the inverse of the coefficient of the variable.

\dfrac{2}{3}d=\dfrac{1}{6}\\\\\dfrac{3}{2}\cdot\dfrac{2}{3}d=\dfrac{3}{2}\cdot\dfrac{1}{6}\\\\d=\dfrac{3\cdot 1}{2\cdot 6}=\dfrac{3}{12}=\dfrac{3\cdot 1}{3\cdot 4}\\\\d=\dfrac{1}{4}

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Finger [1]

ask your teacher.

use a calculator.

Use math tutoring for this module.

Pay more attention to the lecture.

3 0
3 years ago
a survey was taken of children between the ages 7 and 12. let A be the event that the person rides the bus to school, and let B
son4ous [18]

Answer:

The statement is true about whether A and B are independent eventa is fourth option:

A and B are not independent events because P(A/B)=0.375 and P(A)=0.25

Step-by-step explanation:

Let A be the event that the person rides the bus to school, then:

P(A)=75/300

P(A)=0.25

Let B be the event that the person has 3 or more siblings, then:

P(B)=24/300

P(B)=0.25


P(A/B)=9/24

P(A/B)=0.375


Like P(A/B)=0.375 is different to P(A)=0.25 the events are not independent


Answer. Fourth option:

A and B are not independent events because P(A/B)=0.375 and P(A)=0.25

3 0
3 years ago
Find the side of a square whose diagonal measures 15 square root of 2
solmaris [256]

Answer:  15 units .

__________________________________________________

In this case, a square, the two sides of the square (forming a right triangle) are equal), and the "diagonal" forming is the hypotenuse of the right triangle.

In these cases, the measurements of the angles of the right triangle are "45, 45, 90" ; and the measurements of the sides are:  "a, a, a√2" ; in which "a√2" is the hypotenuse.

We are given:  "15√2" is the hypotenuse" ; and we are given that this is a right triangle of a square with a diagonal length (i.e. "hypotenuse" of "15√2" ; so the measure of the side of the "square" (and other two sides of the triangle formed) is:  15 units.   (i.e.,  15, 15, 15√2 ).

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Anna11 [10]

Answer:

2 real solutions

Step-by-step explanation:

Remember this messy thing?

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

The <em>quadratic formula</em>, as it's called, gives us the roots to any quadratic equation in standard form (ax² + bx + c = 0). The information on the <em>type</em> of roots is contained entirely in that bit under the square root symbol (b² - 4ac), called the <em>discriminant</em>. If it's non-negative, we'll have <em>real</em> roots, if it's negative, we'll have <em>complex roots</em>.

For our equation, we have a discrimant of (-3)² - 4(6)(-4) = 9 + 96 = 105, which is non-negative, so we'll have real solutions, and since quadratics are degree 2, we'll have exactly 2 real solutions.

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3 years ago
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