TSR because if u look at the lines of where their similar on the second one you match it up
Answer:
(b) 1.95
Step-by-step explanation:
One of the easiest ways to evaluate an arithmetic expression of almost any kind is to type it into an on-line calculator. Many times, typing it into a search box is equivalent.
<h3>Application</h3>
See the attachment for the search box input (at top) and the result. This calculator has the benefit that it <em>always follows the Order of Operations</em> when evaluating an expression. (Not all calculators do.)
ln(7) ≈ 1.95
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<em>Additional comment</em>
If your math course is asking you to evaluate such expressions, you have probably been provided a calculator to use, or given the requirements for a calculator suitable for use in the course.
There are some very nice calculator apps for phone and tablet. Many phones and tablets already come with built-in calculator apps. For the purpose here, you need a "scientific" or "graphing" calculator. A 4-function calculator will not do.
As with any tool, it is always a good idea to read the manual for your calculator and work through any example problems.
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Years ago, handheld calculators were not available, and most desktop calculators were only capable of the basic four arithmetic functions. Finding a logarithm required use of a table of logarithms. Such tables were published in mathematical handbooks, and extracts of those often appeared as appendices in math textbooks used in school.
F(x) = 5x
for f(7) you replace x with 7 so it will be : f(7) = 5(7) = 35
3/2x-4=20
We simplify the equation to the form, which is simple to understand
3/2x-4=20
We move all terms containing x to the left and all other terms to the right.
+2x=+20+4
We simplify left and right side of the equation.
+2x=+24
We divide both sides of the equation by 2 to get x.
x=12
Answer:
You cab try to divide it evenly as best you can into 5 different sections and then mark them
Step-by-step explanation:
you go in between 1 and -1 and make them go up by fifths to show you work and then just use the numbee line as you know how to