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den301095 [7]
4 years ago
7

A baseball team consists of nine players. How many different batting orders are possible? How many are possible if the pitcher b

ats last?
Mathematics
1 answer:
dmitriy555 [2]4 years ago
3 0

Since the pitcher bats last, there is only one choice for the 9th slot. For the 1st slot, there are 8 choices remaining. For the 2nd slot, there are 7 choices remaining, etc.


So the number of possible batting orders is:
8*7*6*5*4*3*2*1 = 8! = 40,320 
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Answer:

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Step-by-step explanation:

Solve for y:

y^2 + y - 7 = 0

Add 7 to both sides:

y^2 + y = 7

Add 1/4 to both sides:

y^2 + y + 1/4 = 29/4

Write the left hand side as a square:

(y + 1/2)^2 = 29/4

Take the square root of both sides:

y + 1/2 = sqrt(29)/2 or y + 1/2 = -sqrt(29)/2

Subtract 1/2 from both sides:

y = sqrt(29)/2 - 1/2 or y + 1/2 = -sqrt(29)/2

Subtract 1/2 from both sides:

Answer: y = sqrt(29)/2 - 1/2 or y = -1/2 - sqrt(29)/2

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3 years ago
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Write an equation of the line passing through the points (3,1) and (−1, −7).
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Ten less than half of a number(x) is 6.
Likurg_2 [28]

Answer:

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Step-by-step explanation:

Given the following data;

Unknown number = x

Translating the word problem into an algebraic equation, we have;

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We multiply all through by 2;

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Answer:

Total money earned = £1,947.35

Step-by-step explanation:

Given:

Per ticket cost = £3.95

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