Answer:
An example of a data set that satisfies each of these conditions is:
[72, 75, 79, 80, 80, 81, 82, 84, 88, 94, 98]
Step-by-step explanation:
Let's start by defining the terms:
Mean: Average of all numbers
Median: Middle score in a set of given numbers
Mode: Most frequently occuring number
Range: Difference between the lowest and highest number
There are many possible data sets for these conditions, but these are the numbers I found work. I'm sure there is a simpler way to figure this out, but this way makes the most sense to me. This was my process.
We know that all of our numbers need to add up to 913. We know this because our mean is 83 and there are 11 numbers (83X11=913). We can check this by taking 913/11 (the number of scores)=83 (mean)
We know that the median needs to be 81. When the numbers are in order lowest to highest, we would need to have 5 numbers below 81 and 5 numbers above 81. The sixth number in the set should be 81.
We know the mode is 80, so 80 has to be in our data set at least twice with all other numbers appearing less often. This is why I put two 80s and one of every other number in my data set.
I then picked the lowest number in my data set, ensuring that a range of 26 would allow me enough space on both sides of the median. Since I have my lowest number, I can add 26 and get the highest number in my data set.
Once I have the main numbers, I just need to put other numbers before and after the median that would give me a sum of 913 (see the section about the mean). These can be any numbers that go in the right order as long as they don't change any of the numbers we've already established and they total 913.
