The lines shown below are parallel. If the green line has a slope of -3/7, what is
1 answer:
Answer: the slope of green line =
Step-by-step explanation:
We know that,
If two lines are parallel then their slopes(rate of change of y with respect to x) are equal.
Given: The red line and the green line are parallel.
The slope of red line =
Then, the slope of green line = [Slopes of two parallel lines are equal]
Hence, the slope of green line =
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Answer:
∠MSR is right angle
Step-by-step explanation:
It is given that RHOM is a Rhombus
Also ΔHOM, ΔMHR, ΔRHO and ΔOMR are isosceles triangles
Let us take ΔMSR and ΔRSH
∠MRS =∠HRS ( since it is given that the diagonal RO bisects ∠R)
∠RMS =∠RHS ( since Δ MRH is isosceles triangle )
RS = RS ( common side )
By AAS congruency rule ΔMSR ≅ ΔHSR
so we have
∠MSR=∠RSH ( corresponding parts of congruent triangles are congruent)
also we have
∠MSR +∠RSH =180° ( supplementary angles)
∠MSR +∠MSR=180° ( since ∠MSR=∠RSH)
2∠MSR= 180°
∠MSR =90°
Hence ∠MSR is right angle
The transformed figure has the opposite orientation (A'B'C'D' is counterclockwise, whereas ABCD is clockwise), so a reflection is involved. The sgment C'D' is still at the bottom, as is CD, so the reflection must be across a vertical line.
In the attached, the light-blue figure A''B''C''D'' shows the reflection of ABCD across the y-axis. It is easy to see that figure A'B'C'D' is a translation of that 5 units downward.
The appropriate choice is the 2nd one ...
... Reflection over the y-axis followed by a translation down by 5 units.
