Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Answer:
14.60
Step-by-step explanation:
Note that there are 100 centimeters in 1 meter. The plant is 13 meters tall, and grows 8 centimeter every month. It is asking you for 20 months worth (x = 20) of growth.
First, solve for the amount of centimeters total in 20 months:
8 centimeter per month x 20 months = 160 centimeters per 20 months.
Remember, there are 100 centimeters in every meter. Therefore:
160 centimeter/ 100 centimeters per meter = 1.60 meters.
Add the growth to the original height:
13.00 + 1.60 = 14.60
14.60 meters is your answer.
~
Answer:
k = 324
Step-by-step explanation:
Y varies inversely as x
Let k be the constant of variation
Y = k/ x
Y= 36 and x= 9
Substitute the value of Y and x
36 = k/9
Make k the subject of the formula
k= 36*9
k =324
The area of the entire circle is pi*(7)^2, or 49pi.
Due to the 90 degree angle, the area of the larger blue sector is
90
------- * 49 pi = 49/4 units^2
360
The area of the smaller blue sector is
48
------- 49 pi = (2/15)(49 pi) = 98 pi/15 units^2
360
The total area of the blue sectors is the sum of 98 pi/15 and 49 pi/4 (units^2):
59 units^2
Answer: 32°
Step-by-step explanation: see photo
