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notsponge [240]
3 years ago
6

Find a formula for the product P of the solutions of the quadratic equation ax²+bx+c=0 .

Mathematics
1 answer:
Ede4ka [16]3 years ago
8 0

Answer:

product of the roots= c/a

Step-by-step explanation:

The the two roots(α and β) of the quadratic equation ax²+bx+c=0  as given by shridharacharya formula are

\alpha= \frac{-b+\sqrt{b^2-4ac} }{2a}

\beta= \frac{-b-\sqrt{b^2-4ac} }{2a}

now product of the roots

αβ= \frac{-b+\sqrt{b^2-4ac} }{2a}×\frac{-b-\sqrt{b^2-4ac} }{2a}

use formula (a+b)(a-b)= a^2-b^2 and solve we get

αβ= c/a

therefore product of the roots= c/a

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Answer:

(4, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
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Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
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Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = 2x - 7

y = -x + 5

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                                                                                                2x - 7 = -x + 5
  2. [Addition Property of Equality] Isolate <em>x</em> terms:                                            3x - 7 = 5
  3. [Addition Property of Equality] Isolate <em>x</em> term:                                              3x = 12
  4. [Division Property of Equality] Isolate <em>x</em>:                                                       x = 4

<u>Step 3: Solve for </u><em><u>y</u></em>

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  2. Substitute in <em>x</em>:                                                                                                y = -4 + 5
  3. Add:                                                                                                                 y = 1
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vampirchik [111]

Answer:

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Step-by-step explanation:

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