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xxMikexx [17]
3 years ago
13

Which Doesn't Belong?

Mathematics
2 answers:
klio [65]3 years ago
8 0
I’m assuming 9? There isn’t a question so
Kryger [21]3 years ago
8 0

Step-by-step explanation:

If you are goin for which one isn't prime, then it would be four.

If you are going for which one isnt a factor, there is more then one

If you are going for something else, i have no idea.

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Camels are know to lose about 25% of their body weight during times when food and water are scarce. if a camel weighed 1,588 pou
kupik [55]
If you do 25% of 1588 you get 397 LB’s, so the closest one to that would be A.375
4 0
3 years ago
Help pls I'll give 25 points
RideAnS [48]

Answer:

\text{C. }60

Step-by-step explanation:

<u>Question from image</u>:

"The digits 1, 2, 3, 4, and 5 can be formed to arrange 120 different numbers. How many of these numbers will have the digits 1 and 2 in increasing order? For example, 14352 and 51234 are two such numbers."

Let's start by taking a look with the number 1. There are four possible places 1 could be, because there needs to be space for the 2 after it.

Checkmarks mark where the 1 can be, the <em>x</em> marks where it cannot be.

\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{X}

Let's start with the first position:

\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}\:\underline{\#}

There are four places the 2 can be. For each of these four places, we can arrange the remaining 3 digits in 3!=6 ways. Therefore, there are 4\cdot 6=\boxed{24} possible numbers when 1 is the first digit of the number.

Continue this process with the remaining possible positions for 1.

Second position:

\underline{X}\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}

There are three places the 2 can be, since the 2 must be behind the 1. For each of these three places, the remaining 3 digits can be arranged in 3!=6 ways. Therefore, there are 3\cdot 6=\boxed{18} possible numbers when 1 is the second digit of the number.

The pattern continues. Next there will be 2 places to place the 2. For each of these, there are 3!=6 ways to rearrange the remaining 3 digits for a total of 2\cdot 6=\boxed{12} possible numbers when 1 is the third digit of the number.

Lastly, when 1 is the fourth digit of the number, there is only 1 place the 2 can be. For this one place, there are still 3!=6 ways to rearrange the remaining three numbers. Therefore, there are 1\cdot 6=\boxed{6} possible numbers when 1 is the fourth digit of the number.

Thus, there are 24+18+12+6=\boxed{60} numbers that will have the digits 1 and 2 in increasing order, from a set of 120 five-digit numbers created by the digits 1 through 5, where no digit may be repeated.

5 0
2 years ago
What is the value of the function f(x)= -x+4 when x= -2? <br> A) 6<br> B) -6<br> C) -2<br> D) 2
schepotkina [342]
F(x) = -x + 4

Substitute x = -2 to the equation:

f(-2) = -(-2) + 4 = 2 + 4 = 6

Answer: A) 6
7 0
2 years ago
Read 2 more answers
Work out 3% of 860kg<br><br>need this asap!!!
eduard

Answer:

3% of (860 kilograms) =

25.8 kilograms

4 0
2 years ago
Read 2 more answers
Find the exact values of the remaining five trigonometric functions of o satisfying the given conditions.
Lyrx [107]

First, tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>), so if cos(<em>θ</em>) = 3/5 > 0 and tan(<em>θ</em>) < 0, then it follows that sin(<em>θ</em>) < 0.

Recall the Pythagorean identity:

sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1

Then

sin(<em>θ</em>) = -√(1 - cos²(<em>θ</em>)) = -4/5

and so

tan(<em>θ</em>) = (-4/5) / (3/5) = -4/3

The remaining trig ratios are just reciprocals of the ones found already:

sec(<em>θ</em>) = 1/cos(<em>θ</em>) = 5/3

csc(<em>θ</em>) = 1/sin(<em>θ</em>) = -5/4

cot(<em>θ</em>) = 1/tan(<em>θ</em>) = -3/4

4 0
2 years ago
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