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Tju [1.3M]
3 years ago
9

the ramirez family comes home from vacation to find their mailbox overflowing with mail. there are 6 more magazines than there a

re letters. there are twice as many bills as letters. there are 1/3 as many bills as pieces of junk mail. there are 18 pieces of junk mail. how many magazines are there?
Mathematics
1 answer:
nirvana33 [79]3 years ago
4 0

Answer:

9 magazines

Step-by-step explanation:

To solve this problem you will want to work backwards. Start with the junk mail. There is 18 junk mail and if there are 1/3 as many bills as junk mail then you will need to multiply 18 * 1/3. This equals 6 bills. If there is twice as many bills as letters then you will need to divide bills(6) by 2 which equals 3. If there are 6 more magazines than letters then you need to add 6 to the letters (3). 3 + 6 = 9

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7 0
3 years ago
In a triangle ABC, measure of angle B is 90 degrees. AB is 3x-2 units and BC is x+3. If the area of the triangle is 17 sq cm, fo
Scorpion4ik [409]

Answer:

x=\frac{8}{3}\ cm

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

A=\frac{1}{2}(AB)(BC)

we have

A=17\ cm^2

AB=(3x-2)\ cm

BC=(x+3)\ cm

substitute the values

17=\frac{1}{2}(3x-2)(x+3)

34=(3x-2)(x+3)

34=3x^2+9x-2x-6

3x^2+7x-6-34=0

3x^2+7x-40=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

3x^2+7x-40=0

so

a=3\\b=7\\c=-40

substitute in the formula

x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}

x=\frac{-7(+/-)\sqrt{529}} {6}

x=\frac{-7(+/-)23} {6}

x=\frac{-7(+)23} {6}=\frac{16}{6}=\frac{8}{3}

x=\frac{-7(-)23} {6}=-5

therefore

The solution is

x=\frac{8}{3}\ cm

6 0
3 years ago
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The answer is B) 20

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8 0
3 years ago
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Answer:

A . 900-1000

Step-by-step explanation:

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2 years ago
If 16 is added to one-third of a number, the result is three times the number. What is the number?
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First set up the equation based on the description.

\frac{1}{3} x + 16 = 3x

Use subtraction to get the "x"s on one side of the equation. You can next subtract <span>\frac{1}{3} x from both sides.

16 = </span>\frac{8}{3}<span> x

Now you can multiply both sides of the equation by </span>\frac{3}{8}<span>  to solve for x

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