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pickupchik [31]
3 years ago
11

Erry has taken a random sample of students and determined the number of electives that each student in his sample took last year

. There were 19 students in the sample. Here is the data on the number of electives the 19 students took: 6, 6, 8, 7, 7, 7, 8, 9, 10, 8, 7, 6, 9, 6, 8, 7, 9, 7, 10. The mean of this sample data is 7.63.
What would the mean be for a different random sample of 19 students from the same population?
Mathematics
2 answers:
Dafna11 [192]3 years ago
7 0
<h2>Answer with explanation:</h2>

It was given that:

Erry has taken a random sample of  19 students and he took the data as follows:

6, 6, 8, 7, 7, 7, 8, 9, 10, 8, 7, 6, 9, 6, 8, 7, 9, 7, 10.

               The mean of this sample data is 7.63.

<em>As we know that a random sample is one in which each member has an equal chance of getting selected also on the basis of which we can approximately get the information or result for the population.</em>

Hence, when a different random sample of 19 students are selected from the same population. We will observe that the mean would remain approximately the same.

Cerrena [4.2K]3 years ago
6 0
The mean should be about the same, because the sample is random
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Eric and Joshua are playing ping pong and pool. Joshua believes he has a good chance of beating Eric in at least one of the game
Sunny_sXe [5.5K]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Eric and Joshua are playing ping pong and pool. Joshua believes he has a good chance of beating Eric in at least one of the games. The probability Joshua beats Eric in ping pong is 0.48. The probability Joshua beats Eric in pool is 0.46. Joshua is willing to assume the probability of Eric winning a game of ping pong is independent of him winning a game of pool.

Find the probability:

The probability that Joshua beats Eric in ping pong AND pool?

The probability that Joshua beats Eric in ping pong OR pool?

Answer:

P(pp & pool) = 22%

There is 22% probability that Joshua beats Eric in ping pong AND pool.

P(pp OR pool) = 50%

There is 50% probability that Joshua beats Eric in ping pong OR pool.

Step-by-step explanation:

The probability Joshua beats Eric in ping pong is given by

P(pp) = 0.48

The probability Joshua beats Eric in pool is given by

P(pool) = 0.46

The probability that Joshua beats Eric in ping pong AND pool is given by

P(pp & pool) = P(pp)×P(pool)

P(pp & pool) = 0.48×0.46

P(pp & pool) = 0.22

P(pp & pool) = 22%

Therefore, there is 22% probability that Joshua beats Eric in ping pong AND pool.

The probability that Joshua beats Eric in ping pong OR pool is given by

P(pp OR pool) = P(pp)×0.52 + P(pool)×0.54

Where 0.52 is the probability that Eric beats Joshua in the ping pong match (1 - 0.48 = 0.52)

Where 0.54 is the probability that Eric beats Joshua in the pool match (1 - 0.46 = 0.54)

P(pp OR pool) = 0.48×0.52 + 0.46×0.54

P(pp OR pool) = 0.25 + 0.25

P(pp OR pool) = 0.50

P(pp OR pool) = 50%

Therefore, there is 50% probability that Joshua beats Eric in ping pong OR pool.

6 0
3 years ago
Pls help. Have tried this problem a couple times but my answers didnt work
pantera1 [17]

Answer:

infinite solutions...

Step-by-step explanation:

Is there more information to this problem? It can be pretty much anything.

N=3M

Nina can be 30 and Maryna 10, Nina can be 3 and Maryna 1, Nina can be 15 and Maryna 5...

4 0
3 years ago
Read 2 more answers
What is 0.0044 as a percentege
Rashid [163]
0.0044 as a percentage0.44%
7 0
3 years ago
The length of a rectangle is the same as its width. If its perimeter is 32 meters, what is its area?
Fed [463]
The answer would be 64 m2 because it said the length is the same as width so it is basically like a square. The perimeter is 32/4=8 because there are 4 sides in the rectangle. 8 times 8 is 64

The answer is 64 m2
6 0
3 years ago
I BET NO ONE KNOWS THIS y varies jointly as x and z. y=20 when x=2 and z=5 . Find y when x=3 and z=6
Greeley [361]

Hello!

If y varies jointly with x and z, it'll mean that x and z are being multiplied by a factor "k", to equal y.

To give you a visual, this is what I mean.

y=kxz

That means we'll want to find k with the first point we're given: (2,20,5)

20=k(2)(5)

20=10k

k=2

Which means our equation is:

y=2xz

Now, let's plug in the x and z from the other point to find y.

y=2(3)(6)

y=36

Hope this helps!

6 0
3 years ago
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