Answer:
0% probability that more than 100 of the people contacted will purchase your product
Step-by-step explanation:
To solve this question, i am going to use the binomial approximation to the normal.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:

The standard deviation of the binomial distribution is:

Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that
,
.
In this problem, we have that:

So


What is the probability that more than 100 of the people contacted will purchase your product?
This is 1 subtracted by the pvalue of Z when X = 100. So



has a pvalue of 1
1 - 1 = 0
0% probability that more than 100 of the people contacted will purchase your product