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3 years ago

Which of the following is true concerning hull fouling from commercial shipping and recreational boating?

Mathematics

2 answers:

user100 [1]3 years ago

4 0

Answer: C. It is difficult to prevent since ship hulls begin, conduct, and end voyages in water.

Step-by-step explanation:

guajiro [1.7K]3 years ago

4 0

Answer:

Step-by-step explanation:

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I will give brainliest.

butalik [34]

17, you only have to add up a few because of the x and y placements. Hope this helps you :)

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3 years ago

Read 2 more answers

What is (8 × 10 -3 )(.0003) in scientific form.

murzikaleks [220]

Answer:

2.31 ×10 ^− 2

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the

10 . If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

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3 years ago

A variable force of magnitude F(x) moves a body of mass m along the x-axis from x1 to x2. The net work done by the force in movi

kicyunya [14]

Answer:

$w=\frac{1}{2}m(v^2_2-v^2_1)$

Step-by-step explanation:

We are given that a variable force of magnitude F(x) moves a body along the x- axis from $x_1$ to $x_2$ .

The net work done by the force in moving the body from $x_1$ to $x_2$ .

$v_1$ =Velocity of the body at $x_1$

$v_2=$ Velocity of the body at $x_2$

We know that

Work done=Final kinetic energy-Initial kinetic energy

$w=\frac{1}{2}mv^2_2-\frac{1}{2}mv^2_1$

K.E= $\frac{1}{2}mv^2$

$Net\;work \;done=\frac{1}{2}m(v^2_2-v^2_1)$

Hence, the net work done by the force is given by

$w=\frac{1}{2}m(v^2_2-v^2_1)$

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3 years ago

A total of $5500 was invested in two accounts. Part was invested in a CD at 2% annual

ivanzaharov [21]

I think the answer is 800$

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3 years ago

14. DECORATING Sabrina is decorating her

Nikitich [7]

Answer:

what are you trying to find?

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3 years ago