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3 years ago

Calculate the area of the given circle.

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

5 0

Answer:

Using the formula for Area of circle_

πr²

putting values_

π = 3.14

r² = (5)² = 25.

Therefore,

3.14 × 25

= 78.5

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. If f(x) = 7x2 – 3x + 7, find f(2) + f(–1) + f(0).

alexandr402 [8]

<h2>♪Answer : </h2>

»f(x) = 7x² - 3x + 7

find f(2) in f(x)

»f(2) = 7(2)² - 3(2) + 7

»f(2) = 7(4) - 6 + 7

»f(2) = 28 - 6 + 7

»f(2) = 29

find f(-1) in f(x)

»f(-1) = 7(-1)² - 3(-1) + 7

»f(-1) = 7(1) + 3 + 7

»f(-1) = 7 + 3 + 7

»f(-1) = 17

find f(0) in f(x)

»f(0) = 7(0)² - 3(0) + 7

»f(0) = 7(0) - 0 + 7

»f(0) = 0 - 0 + 7

»f(0) = 7

so, f(2) + f(-1) + f(0) is

29 + 17 + 7
= 53✅

7 0

3 years ago

EXPLAIN FOR BRAINLIEST<br> 45 POINTS

raketka [301]

The answer is 8km.

1:100,000 = 1.6 miles = 1 kilometer x 8 = 8 km

4 0

3 years ago

Mr. Blackwell’s company produces nuts and bolts. The total monthly profit for his company was $76,378. The profit earned from nu

Artist 52 [7]

Answer:

Step-by-step explanation:

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3 years ago

Halle has two ribbons. The blue ribbon is 58 cm. The green ribbon is 38 cm longer than the blue ribbon.

pashok25 [27]

Answer:

a) green ribbon is 96cm long

b) 29cm is left

Step-by-step explanation:

a) length of green ribbon = 58cm + 38cm = 96cm

b) length of green ribbon left = 96cm - 67cm = 29cm

5 0

4 years ago

Ms. Rivera created two dot plots to compare the results of her recent science quiz for 1st period students compared to 7th perio

Lorico [155]

The dot plots is an illustration of charts and graphs

The average score of period 7 is greater than the average score of period 1

<h3>How to determine the period with the higher average?</h3>

From the dot plots in the complete question, we have the following frequency tables

<u>Period 1</u> <u>Period 7</u>

Score Students Score Students

55 1 65 1

70 1 75 3

75 6 80 5

80 6 85 6

85 2 90 3

90 3 95 2

95 1

The average is calculated using:

$\bar x = \frac{\sum fx}{\sum f}$

For period 1, we have:

$\bar x_1 = \frac{55 * 1 + 70 * 1 + 75 * 6 + 80 * 6 + 85 * 2 + 90 * 3 + 95 * 1}{1 + 1 + 6 + 6 + 2 + 3 + 1}$

Evaluate the sum

$\bar x_1 = \frac{1590}{20}$

Evaluate the quotient

$\bar x_1 = 79.5$

For period 7, we have:

$\bar x_7 = \frac{65 * 1 + 75 * 3 + 80 * 5 + 85 * 6 + 90 * 3 + 95 * 2}{1 + 3 + 5 + 6 + 3 + 2}$

Evaluate the sum

$\bar x_7 = \frac{1660}{20}$

Evaluate the quotient

$\bar x_7 = 83$

By comparison, 83 is greater than 79.5

Hence, the average score of period 7 is greater than the average score of period 1