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3 years ago

Calculate the area of the given circle.

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

5 0

Answer:

Using the formula for Area of circle_

πr²

putting values_

π = 3.14

r² = (5)² = 25.

Therefore,

3.14 × 25

= 78.5

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Joe has 4 less than 7 times as many shirts as Mark. Together, Joe and Mark have 140 shirts. How many shirts does Joe have? How m

lara [203]

Answer:

Mark has 18 shirts

Given that together they have 140 shirts.

x + 7x - 4 = 140

8x = 140 + 4

8x = 144

x = 144/8

x = 18

Joe has 122 shirts

7x - 4

7 × 18 - 4

126 - 4

= 122

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2 years ago

What is the relationship between the Boston Tea Party and the Tea Act?

Ugo [173]

Answer:

the Boston tea party is the effect of the tea act(Britain started taxing tea and making them buy from a specific company). After the Boston tea party, England shut down their ports and dissolved their local government.

Step-by-step explanation:

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3 years ago

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lilavasa [31]

The turtle is crawling at a rate of 1 mile per hour or 1 mph.

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4 years ago

Read 2 more answers

Determine the common ratio and find the next three terms of the geometric sequence 9,3sqrt3,3

Maru [420]

Answer:

Fourth term: $a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{3}$ = $\sqrt{3}$

Fifth term: $a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{4}$ = 1

Sixth term: $a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}$

Step-by-step explanation:

The geometric progression is:

$9, 3 \sqrt{3}, 3...$

The first term, a, is 9

To find the common ratio, r, all we have to do is divide a term by its preceding term.

Let us divide the second term by the first:

$r = \frac{3\sqrt{3}}{9}\\ \\r = \frac{\sqrt{3}}{3}$

That is the common ratio.

Geometric progression is given generally as:

$a_n = ar^{(n - 1)}$

where a = first term

r = common ratio

$a_n$ = nth term

We need to find the 4th, 5th and 6th terms.

Fourth term: $a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{3}$ = $\sqrt{3}$

Fifth term: $a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)}$ = $9 * (\frac{\sqrt{3}}{3})^{4}$ = 1

Sixth term: $a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}$

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3 years ago

Can you please help me list the forms As_,_ and limits

Anastasy [175]

Given the function:

$f(x)=\frac{2x+1}{x}$

First, the graph of the function will be as shown in the following figure:

For the given rational function, we will find the following:

Domain = ( -∞, 0 ) ∪ ( 0, ∞ )

Range = ( -∞, 2) ∪ (2, ∞ )

Increasing = Φ

Decreasing = ( -∞, 2) ∪ (2, ∞ )

All asymptotes:

Vertical asymptote: x = 0

Horizontal Asymptote: y = 2

All limits:

$\begin{gathered} \lim _{x\rightarrow-\infty}f(x)=2 \\ \lim _{x\rightarrow\infty}f(x)=2 \\ \lim _{x\rightarrow0^-}f(x)=-\infty \\ \lim _{x\rightarrow0^+}f(x)=\infty \end{gathered}$

3 0

2 years ago