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n200080 [17]
3 years ago
6

An insurance adjuster processes the claims of six policy holders in an eight hour work day. The adjuster uses $5 in gasoline and

$3 in forms and office supplies to complete the work. What is her labor productivity?
a) $1 per claim
b) 1 claim per dollar
c) 1.33 hours per claim
d) 0.75 claims per hour
Mathematics
1 answer:
Bad White [126]3 years ago
6 0

Answer:

D

Step-by-step explanation:

Labor productivity is is measured per hours.

Hence, the work he does [amount of claims] will be distributed amongst the amount of hours he works. The amount of dollar he uses <em>doesn't matter for labor productivity.</em>

<em />

Thus, his work is 6 claims. He does that is 8 hours. So claim/hr is:

6/8 = 0.75 claims per hour

Answer choice D is right.

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In a math class with 27 students, a test was given the same day that an assignment was due. There were 17 students who passed th
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Answer:

The probability that a student who completed the homework failed the test is 0.211.

Step-by-step explanation:

The probability of an event <em>E</em> is the ratio of the favorable number of outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

The conditional probability of an event <em>A</em> given that another event <em>B</em> has already occurred is:

P(A|B)=\frac{P(A\cap B)}{P(B)}

Denote the events as follows:

P = a student passes the test

F = a student fails the test

X = a student completes the assignment

Y = a student does not completes the assignment

From the information provided the summary table is as follows:

             P            F         Total

 X         <u>15</u>           <u>4</u>           19

 Y          <u>2</u>            <u>6</u>            <u>8</u>

Total      17          <u>10</u>          27

Compute the probability that a student completed the assignment and failed the test as follows:

P(X\cap F)=\frac{n (X\cap F)}{N}=\frac{4}{27}

Compute the probability that a student completed the assignment as follows:

P(X)=\farc{19}{27}

Compute the probability that a student failing the test given that the student completed the assignment as follows:

P(F|X)=\frac{P(X\cap F)}{P(X)}=\frac{4/27}{19/27}=\frac{4}{19}=0.21053\approx 0.211

Thus, the probability that a student who completed the homework failed the test is 0.211.

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