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n200080 [17]
3 years ago
6

An insurance adjuster processes the claims of six policy holders in an eight hour work day. The adjuster uses $5 in gasoline and

$3 in forms and office supplies to complete the work. What is her labor productivity?
a) $1 per claim
b) 1 claim per dollar
c) 1.33 hours per claim
d) 0.75 claims per hour
Mathematics
1 answer:
Bad White [126]3 years ago
6 0

Answer:

D

Step-by-step explanation:

Labor productivity is is measured per hours.

Hence, the work he does [amount of claims] will be distributed amongst the amount of hours he works. The amount of dollar he uses <em>doesn't matter for labor productivity.</em>

<em />

Thus, his work is 6 claims. He does that is 8 hours. So claim/hr is:

6/8 = 0.75 claims per hour

Answer choice D is right.

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For a data set of the pulse rates for a sample of adult? females, the lowest pulse rate is 39 beats per? minute, the mean of the
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Answer:

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b) So 3.07 standard deviations below the mean.

c) Z = -3.07.

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

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Mean \mu = 74, standard deviation \sigma = 11.4

a. What is the difference between the pulse rate of 39 beats per minute and the mean pulse rate of the? females?

39 - 74 = -35

The difference is of 35 beats per minute.

b. How many standard deviations is that? [the difference found in part? (a)?

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Z = \frac{X - \mu}{\sigma}

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|Z| = 3.07

So 3.07 standard deviations below the mean.

c. Convert the pulse rate of 39 beats per minutes to a z score.

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