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zvonat [6]
2 years ago
7

The high-school football team scored 19 points on touchdowns (worth 7 points if you count the extra point) and field goals (wort

h 3 points). If the team scored 5 times, how many of each type did they score?
Mathematics
1 answer:
Kazeer [188]2 years ago
5 0
If they scored 5 times, they got 1 touchdown and 4 field goals.

Equation:

7 + 3 + 3 + 3 + 3 = 19.


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(8z^8/4z^4)^-4 please help me to solve this
Anni [7]
8 / 4 = 2 ;
z^8 / z^4 = z^4 ;
then, 8z^4 / 4z^4 = 2z^4 ;
finally, ( 8z^4 / 4z^4 )^ -4 = ( 2z^4 )^ - 4 = 1 / ( 2z^4 )^4 = 1 / [ 2^4 * ( z^4 )^ 4 ] = 1 / ( 16 * z^16 )
4 0
3 years ago
Please help me! Have to get it done before 5
qwelly [4]
I’m not sure about the first 2
8 0
3 years ago
Read 2 more answers
Please don't answer wrong.​
Tamiku [17]

Answer:

<h3><u>Part (a)</u></h3>

<u />

<u>Equation of a circle</u>

(x-a)^2+(y-b)^2=r^2

where:

  • (a, b) is the center
  • r is the radius

Given equation:  x^2+y^2=6.25

Comparing the given equation with the general equation of a circle, the given equation is a <u>circle</u> with:

  • center = (0, 0)
  • radius = \sqrt{6.25}=2.5

To draw the circle, place the point of a compass on the origin. Make the width of the compass 2.5 units, then draw a circle about the origin.

<h3><u>Part (b)</u></h3>

Given equation:  x+y=1.5

Rearrange the given equation to make y the subject:  y=-x+1.5

Find two points on the line:

x=-2 \implies -(-2)+1.5=3.5\implies (-2,3.5)

x=2 \implies -(2)+1.5\implies-0.5\implies (2,-0.5)

Plot the found points and draw a straight line through them.

The <u>points of intersection</u> of the circle and the straight line are the solutions to the equation.

To solve this algebraically, substitute  y=-x+1.5  into the equation of the circle to create a quadratic:

\implies x^2+(-x+1.5)^2=6.25

\implies x^2+x^2-3x+2.25=6.25

\implies 2x^2-3x-4=0

Now use the quadratic formula to solve for x:

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

\implies x=\dfrac{-(-3) \pm \sqrt{(-3)^2-4(2)(-4)}}{2(2)}

\implies x=\dfrac{3 \pm \sqrt{41}}{4}

To find the coordinates of the points of intersection, substitute the found values of x into y=-x+1.5

\implies y=-\left(\dfrac{3 + \sqrt{41}}{4}\right)+1.5=\dfrac{3-\sqrt{41}}{4}

\implies y=-\left(\dfrac{3 - \sqrt{41}}{4}\right)+1.5=\dfrac{3+\sqrt{41}}{4}

Therefore, the two points of intersection are:

\left(\dfrac{3 + \sqrt{41}}{4},\dfrac{3-\sqrt{41}}{4}\right) \textsf{ and }\left(\dfrac{3 - \sqrt{41}}{4},\dfrac{3+\sqrt{41}}{4}\right)

Or as decimals to 2 d.p.:

(2.35, -0.85) and (-0.85, 2.35)

6 0
2 years ago
If the perimeter is 74mm and the width 16mm what is the length
weqwewe [10]
P=2w+2l
74=2(16)+2l
74=32+2l
42=2l
21=l

The length is 21 mm.
4 0
3 years ago
Read 2 more answers
3. If you were to graph the equation y = -x + 1 and graph the equation y
Nat2105 [25]

Answer: (3, -2)

Step-by-step explanation: graphed both of em on desmos and thats the intersection.

5 0
2 years ago
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