8 / 4 = 2 ;
z^8 / z^4 = z^4 ;
then, 8z^4 / 4z^4 = 2z^4 ;
finally, ( 8z^4 / 4z^4 )^ -4 = ( 2z^4 )^ - 4 = 1 / ( 2z^4 )^4 = 1 / [ 2^4 * ( z^4 )^ 4 ] = 1 / ( 16 * z^16 )
I’m not sure about the first 2
Answer:
<h3><u>Part (a)</u></h3>
<u />
<u>Equation of a circle</u>

where:
- (a, b) is the center
- r is the radius
Given equation: 
Comparing the given equation with the general equation of a circle, the given equation is a <u>circle</u> with:
- center = (0, 0)
- radius =

To draw the circle, place the point of a compass on the origin. Make the width of the compass 2.5 units, then draw a circle about the origin.
<h3><u>Part (b)</u></h3>
Given equation: 
Rearrange the given equation to make y the subject: 
Find two points on the line:


Plot the found points and draw a straight line through them.
The <u>points of intersection</u> of the circle and the straight line are the solutions to the equation.
To solve this algebraically, substitute
into the equation of the circle to create a quadratic:



Now use the quadratic formula to solve for x:



To find the coordinates of the points of intersection, substitute the found values of x into 


Therefore, the two points of intersection are:

Or as decimals to 2 d.p.:
(2.35, -0.85) and (-0.85, 2.35)
P=2w+2l
74=2(16)+2l
74=32+2l
42=2l
21=l
The length is 21 mm.
Answer: (3, -2)
Step-by-step explanation: graphed both of em on desmos and thats the intersection.