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Mashcka [7]
3 years ago
12

Recall that within the ArrayBoundedQueue the front variable and the rear variable hold the indices of the elements array where t

he current front and rear elements, respectively, of the queue are stored. Which of the following code sequences could be used to correctly enqueue element into the queue, assuming that enqueue is called on a non-full queue and that the code also correctly increments numElements
Computers and Technology
1 answer:
Citrus2011 [14]3 years ago
6 0

Answer:

int n = elements.length;

if(rear < n) {

rear = (rear + 1) % n;

elements[rear] = element;

rear = rear + 1;

}

Explanation:

Options are not made available; However, I'll answer the question base on the following assumptions.

Assumptions

Array name = elements

The front and the rear variable hold the current indices elements

Element to enqueue is "element" without the quotes

To enqueue means to add an element to an already existing queue or to a new queue.

But first, the queue needs to be checked if it can accept a new element or not; in other words, if it's full or not

To do this, we check: if rear < the length of the queue

If this statement is true then it means the array can accept a new element; the new element will be stored at elements[rear] and the rear will be icremented by 1 rear by 1

Else if the statement is false, then an overflow is said to have occurred and the element will not be added.

Going by the above explanation, we have

int n = elements.length;

if(rear < n) {

rear = (rear + 1) % n;

elements[rear] = element;

rear = rear + 1;

}

Additional explanation:

The first line calculates the length of the queue

The if condition on line 2 tests if the array can still accept an element or not

Let's assume this statement is true, then we move to liine 3

Line 3 determines the new position of rear.

Let's assume that n = 6 and current rear is 4.

Line 3 will produce the following result;

rear = (rear + 1) % n;

rear = (4 + 1)% 6

rear = 5%6

rear = 5.

So, the new element will be added at the 5th index

Then line 4 will be equivalent to:

elements[rear] = element;

elements[5] = element;

Meaning that the new element will be enqueued at the 5th index.

Lastly, rear is incremented by 1 to denote the new position where new element can be added.

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Answer:

Answered in C++

#include <iostream>

using namespace std;

int main() {

   int size;

   cout<<"Length of array: ";

   cin >> size;

   double *numDoubles = new double[size];

   double sum =0;

   cout<<"Array Elements: ";

   for(int i=0;i<size;i++){

       cin>>numDoubles[i];

       sum += numDoubles[i];

   }

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   return 0;  

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Explanation:

This line declares the size (or length) of the array

<em>    int size; </em>

This line prompts the user for the array length

<em>    cout<<"Length of array: "; </em>

This gets the input from the user

<em>    cin >> size; </em>

This dynamically declares the array as of double datatype

<em>    double *numDoubles = new double[size]; </em>

This declares and initializes sum to 0

<em>    double sum =0; </em>

This prompts the user for elements of the array

<em>    cout<<"Array Elements: "; </em>

The following iteration gets input from the user and also calculates the sum of the array elements

<em>    for(int i=0;i<size;i++){ </em>

<em>        cin>>numDoubles[i]; </em>

<em>        sum += numDoubles[i]; </em>

<em>    } </em>

This deletes the array

<em>    delete [] myarray; </em>

This calculates and prints the average of the array

<em>    cout<<"Average: "<<sum/size; </em>

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