(10 * 50) / 100
Multiply 10 and 50
500/100
500 divide by 100
The answer is 5
we know that
The measure of the external angle is the semidifference of the arcs that it covers
so
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
Let
x------> minor arc MN
major arc MN=360-x
substitute in the formula above
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x
x=104.14°
therefore
the answer is
the measure of arc MN (minor arc) is 104.14°
Answer:
if i am rightthe two other angles arre 39
Step-by-step explanation:
if a triganle is 180 degrees and you have already one angle then all you do is subtract 180 and 102
180-102= 78
then since you need the other two angles all you do is divide it by 2
so 78/2= 39 so the two missing anlges are 39
