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3 years ago

5

The distance between two towns on a map is 9 centimeters. the actual distance between two towns is 63 kilometers. what is the sc

ale on the map?

2 answers:

Vlad1618 [11]3 years ago

8 0

Answer:

7

Step-by-step explanation:

Ilia_Sergeevich [38]3 years ago

5 0

If your trying to find the unit rate or the scale of the map, you need to figure out how many kilometers are per centimeters. To get that you need to do 63 divided by 9, witch would get you 7. So to my ability, the answer would be 1 cm per 7 kilometers. Hopefully this answer helped you and I'm hoping its correct.

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Graph each absolute value function. State the domain, range, and y-intercept.

Inessa05 [86]

Answer:

i. D:All real numbers

ii.R: $y\le-2$

iii. Y-int: $b=-2.5$

Step-by-step explanation:

The given function is

$y=-\frac{1}{2} |x-1|-2$

The domain of this function are the values of x that makes the function defined.

The absolute value function is defined for all real values.

The domain is all real numbers.

ii. The range refers to the values of y for which x is defined.

$y=-\frac{1}{2} |x-1|-2$

The vertex of this function is

$(1,-2)$

The function is reflected in the x-axis.

The vertex is therefore the maximum point on the graph of the function.

The range is therefore;

$y\le-2$

Or

$(-\infty,2]$

iii. To find the y-intercept, we substitute $x=0$ into the funtion.

$y=-\frac{1}{2} |0-1|-2$

$y=-\frac{1}{2} (1)-2$

$y=-2.5$

The y-intercept is $b=-2.5$

The graph is shown in the attachment.

3 0

3 years ago

Please calculate this limit <br>please help me

Tasya [4]

Answer:

We want to find:

$\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}$

Here we can use Stirling's approximation, which says that for large values of n, we get:

$n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n$

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

$\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} = \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}$

Now we can just simplify this, so we get:

$\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\$

And we can rewrite it as:

$\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}$

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

$\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}$

7 0

3 years ago

Help !!! with 14 please :))

BartSMP [9]

Since p is an obtuse angle
& that it's between two acute angles

3 0

3 years ago

Statements that are true for a cylinder with radius r and height h.

vampirchik [111]

Answer:

Only the second and third statements are correct:

Doubling <em>r</em> quadruples the volume.

Doubling <em>h</em> doubles the volume.

Step-by-step explanation:

The volume of a cylinder is given by:

$\displaystyle V=\pi r^2h$

We can go through each statement and examine its validity.

Statement 1)

If the radius is doubled, our new radius is now 2<em>r</em>. Hence, our volume is:

$\displaystyle V=\pi (2r)^2h=4\pi r^2h$

So, compared to the old volume, the new volume is quadrupled the original volume.

Statement 1 is not correct.

Statement 2)

Using the previous reasonsing, Statement 2 is correct.

Statement 3)

If the height is doubled, our new height is now 2<em>h</em>. Hence, our volume is:

$V=\pi r^2(2h)=2\pi r^2h$

So, compared to the old volume, the new volume has been doubled.

Statement 3 is correct.

Statement 4)

Statement 4 is not correct using the previous reasonsing.

Statement 5)

Doubling the radius results in 2<em>r</em> and doubling the height results in 2<em>h</em>. Hence, the new volume is:

$V=\pi (2r)^2(2h)=\pi (4r^2)(2h)=8\pi r^2h$

So, compared to the old volume, the new volume is increased by eight-fold.

Statement 5 is not correct.

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3 years ago

Solve the system of equations. <br><br> 10x+y=−20 <br><br> y=2x2−4x−16<br><br> ( , ) and ( , )

Sladkaya [172]

I will go about solving this using the elimination method.

First, convert the equations.

10x + y = -20
4x + y = -12

Second, find the easiest variable to get rid of and get rid of it! (In this case, y) We will subtract to get rid of y.

6x = -8

Third, you want to solve the equation.

6x = -8 (divide by 6)
x = $-1 \frac{1}{3}$

Fourth, solve for y by inserting the answer for x into one of the equations.

10( $-1 \frac{1}{3}$ ) + y = -20
$-13 \frac{1}{3}$ + y = -20 (subtract $-13 \frac{1}{3}$ )
y = $-6 \frac{2}{3}$

The solution for this system of equations is ( $-1 \frac{1}{3}$ , $-6 \frac{2}{3}$ ).

7 0

3 years ago

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