Answer:
≈ 78.55 cm
Step-by-step explanation:
Using the ratio of arc (AB) to circumference (C) is equal to the ratio of angle subtended at centre by arc AB to 360°, that is
= , that is
= ( cross- multiply )
110C = 8640 ( divide both sides by 110 )
C = ≈ 78.55 cm ( to 2 dec. places )
Answer:
no it is not perpedicular
Step-by-step explanation:
I plugged the equation into a graphing calculator and the line does not appear to be perpendicular
Answer:
Step-by-step explanation:
232/2=116
so 116,116 has maximum product
Answer:
The ordered pairs are;
(-1,1) and (-2,3)
Step-by-step explanation:
Here, we want to select which ordered pair is not a solution to the given equation
The one that will not be a solution will be a point at which if we insert the x-value into the equation, we do not get the y-value at that point
For (3,7
2(3) + 1 = 7
For 0,1
2(0) + 1 = 1
For (-1,1)
= 2(-1) + 1 = -2 + 1 = -1
This is wrong
(-3,-5)
= 2(-3) + 1 = -6 + 1 = -5
(-2,3)
= 2(-2) + 1 = -4 + 1 = -3
This is wrong also
Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.