I think that it could possibly be 12 feet but at the same time I'm not sure
Answer:
The dimensions of the rectangular box, x = y = z = 0.817 cm
Step-by-step explanation:
Given;
total surface area of the rectangular box or cuboid = 4 cm²
A rectangular box with largest volume is a cube.
The total surface area of a cube = 6 times square of one edge length.
Let the edge length = given dimensions, x, y, z
x = y = z
6x² = 4
x² = 4/6
Therefore, the dimensions of the rectangular box, x = y = z = 0.817 cm
Answer:
For The value of a = 0 and c = 0 , The given expression equality is true
Step-by-step explanation:
Given expression as :
= a - 2
Or, 3 a² + ac + 2 c - 6 a = ( a - 2 ) × ( 3 a - c )
Or, 3 a² + ac + 2 c - 6 a = 3 a² - ac - 6 a + 2 c
Or, ( 3 a² + ac + 2 c - 6 a ) - ( 3 a² - ac - 6 a + 2 c ) =0
Or, ( 3 a² - 3 a² ) + ( ac + ac ) + ( 2 c - 2 c ) + ( - 6 a + 6 a ) = 0
or, 0 + 2 ac + 0
Or, 2 ac = 0
∴ a =0 and c = 0
Hence For The value of a = 0 and c = 0 , The given expression equality is true . Answer
Answer:
i might be wrong but i think its 5:19
Step-by-step explanation:
<h3>
Answer: </h3><h3>
speed of train A = 44 mph</h3>
=============================================
Work Shown:
x = speed of train A
y = speed of train B
"train A travels 4/5 the speed of train B" (I'm assuming "train one" is supposed to read "train B"). So this means x = (4/5)y
distance = rate*time
d = x*7
d = (4/5)y*7 = (28/5)y represents the distance train A travels
d = y*7 = 7y represents the distance train B travels
summing those distances will give us 693
(28/5)y + 7y = 693
5*( (28/5)y + 7y ) = 5*693
28y + 35y = 3465
63y = 3465
y = 3465/63
y = 55
Train B's speed is 55 mph
4/5 of that is (4/5)y = (4/5)*55 = 4*11 = 44 mph
Train A's speed is 44 mph