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Elena-2011 [213]
3 years ago
13

What is the expanded from for 430,290,100

Mathematics
2 answers:
Anton [14]3 years ago
4 0
400,000,000+30,000,000+200,00+90,000+100 is it 
grin007 [14]3 years ago
3 0
400,000,000 + 30,000,000 + 200,000 + 90,000 +100
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HELP PLZS FAST BRAINIEST
kirill115 [55]

Answer:

x=-2, y=-2. (-2, -2).

Step-by-step explanation:

2x-5y=6

-2x+10y=-16

-------------------

5y=-10

y=-10/5=-2

2x-5(-2)=6

2x+10=6

2x=6-10

2x=-4

x=-4/2=-2

3 0
2 years ago
Read 2 more answers
HELP PLEASE!!!
VMariaS [17]

Answer:

Neither

Step-by-step explanation:

First, you need to put your equations in y=mx+b form

Your first equation...

5x + 4y = 3

4y = 3-5x

y = -5/4x + 3/4

Your second equation...

5x-4y = -3

-4y = -5x -3

y = 5/4x + 3/4

The slopes aren't the same and are not reciprocals, so the answer would be neither.  

7 0
2 years ago
Tim is 35 years old. He is 7 years younger than 6 times his daughter's age. The equation,
Oksana_A [137]

Answer:

A. 7 years old

Step-by-step explanation:

6x-7=35 is the equation.

Add 7 to both sides, which gives you 6x=42.

Then both sides by 6, so 6/6=x and 42/6=7

So, x=7.

Since x is his daughter's age, x=7, so his daughter is 7.

6 0
2 years ago
Read 2 more answers
Two fifths of the cross-country team arrived at the weight room at 7 a.m. Ten minutes later, 3/10 of the team showed up. The res
frosja888 [35]

Answer:

7/10 of the team showed up

Step-by-step explanation:

5 0
3 years ago
Find f. f ″(x) = x^−2, x > 0, f(1) = 0, f(6) = 0
marin [14]

If you do in fact mean f(1)=f(6)=0 (as opposed to one of these being the derivative of f at some point), then integrating twice gives

f''(x) = -\dfrac1{x^2}

f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1

f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2

From the initial conditions, we find

f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0

f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)

Eliminating C_2, we get

(C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))

-5C_1 = \ln(6)

C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)

Then

\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}

3 0
2 years ago
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