First, write out the statement as an inequality so that it looks like this: x<span>≤11/5
Then you graph it on a number line, and since you know anything greater/less than or equal to is a closed circle since it includes the value 11/5, you would plot a closed circle on 11/5 on a number line and draw and arrow pointing towards the left to show that only values 11/5 or under can satisfy x.
</span>
        
             
        
        
        
Answer:
The smallest positive integer solution to the given system of congruences is 30.
Step-by-step explanation:
The given system of congruences is


where, m and n are positive integers.
It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as



Now, we can say that m>n because m and n are positive integers.
For n=1,


19 is not divisible by 5 so m is not an integer for n=1.
For n=2,



The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is

Therefore the smallest positive integer solution to the given system of congruences is 30.
 
        
             
        
        
        
Answer:
10y + 29 ≤ -23
Step-by-step explanation:
subtract 29 from each side to get:
10y ≤ -52
y ≤ -5.2
 
        
             
        
        
        
Answer:
y = -7x + 2
Step-by-step explanation: