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Jet001 [13]
3 years ago
9

What is a set of tree numbers that have a gaff of 13

Mathematics
1 answer:
asambeis [7]3 years ago
8 0
It's not clear what "tree numbers" or a "gaff" are.
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Find volume with full working out pls asap
ZanzabumX [31]

Answer:

868 m³

Step-by-step explanation:

Volume = Difference of cones

V = ⅓(pi×r²h)

Volume of cone with base Circle O:

h = 8.2+8.2 = 16.4 m

V1 = ⅓(pi×7.6²×16.4)

V1 = 991.97

Volume of cone with base Circle A:

V2 = ⅓(pi×3.8²× 8.2)

V2 = 124 m³

Volume = V1 - V2

991.97 - 124 = 868 m³

6 0
3 years ago
CAN ANYONE HELP ME PLEASE!!!!!!
HACTEHA [7]
Not sure if this helps

3 0
3 years ago
Consider the intersecting lines shown. Which of the following statements is true?
elixir [45]

Answer:

C. m∠x + m∠y = 180

Step-by-step explanation:

The two straight line in the diagram intersect each other to form two pairs of vertical angles. These are <x and <z, and <y and w.

The only statement from the given options that is true is m∠x + m∠y = 180.

This is because they are angles in a straight line. The sun of angles in a straight line is 180°.

3 0
3 years ago
Write the point-slope form of the equation of the horizontal line that passes through the point (2, 1). Pease show how!
mote1985 [20]
Check the picture below.

using a second for it, since it's a horizontal line, then say hmmm we'll use the y-intercept, or (0, 1), so the equation of a line that passes through (2,1) and (0,1)

\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;&({{ 2}}\quad ,&{{ 1}})\quad &#10;%   (c,d)&#10;&({{ 0}}\quad ,&{{ 1}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-1}{0-2}\implies \cfrac{0}{-2}&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-1=0(x-2)

5 0
3 years ago
One-stray Problem Solving
anygoal [31]
A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
__
a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
__
c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
3 0
2 years ago
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