Answer:
The probability that a randomly selected call time will be less than 30 seconds is 0.7443.
Step-by-step explanation:
We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.
Let X = caller times at a customer service center
The probability distribution (pdf) of the exponential distribution is given by;

Here,
= exponential parameter
Now, the mean of the exponential distribution is given by;
Mean =
So,
⇒
SO, X ~ Exp(
)
To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;
; x > 0
Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)
P(X < 30) =
= 1 - 0.2557
= 0.7443
In Y=-3x+5 the slope is: -3 and the Y intercept is 5.
Explanation:
The equation without any actual inputs is: Y=mX+B. m refers to the slope. B is the Y intercept. So when looking at the equation with information inputted. You would follow the same structure. Slope will be with the X and Y intercept will be added after.
Answer:
20 - 0.9u = 4.7
-0.9u = 4.7 - 20
-0.9u = -15.3
Divide both sides by - 0.9
u = 17
Hope this helps.
I believe the answer is C!
Answer:10x
Step-by-step explanation:
yes