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3 years ago

12

An item on sale costs 80% of the original price. The original price was $22.

1 answer:

sergejj [24]3 years ago

8 0

Answer:

17.6

Step-by-step explanation:

22 x .80 =17.6

17.6 is 80% of 22 so that would be your answer

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Suppose we fit a regression line to predict the number of incidents of skin cancer per 1,000 people from the number of sunny day

Jet001 [13]

Answer: The incidence of skin cancer (melanoma) has been underestimated.

Step-by-step explanation: The frequency of melanoma is more than 20 times higher in whites than in black Americans. In general, the risk of melanoma in the course of life is approximately 2.6% (1 in 38) for whites, 0.1% (1 in 1.000) for black people and 0.58% (1 in 172) for Hispanics. the risk for each person can be affected by a different number of factors.

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3 years ago

Suppose x is any positive number. Circle 1: center (0, 0) and radius 2x Circle 2: center (0, 0) and radius 10x Why is circle 1 s

Alexeev081 [22]

Answer:

Because both have the center of (0,0)

3 0

3 years ago

How do you do this problem? 3x+1=10

Vlad1618 [11]

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5 0

3 years ago

Read 2 more answers

Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi

ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles carry just one person.

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

$P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291$

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

$\mu = np = 92(0.64) = 58.88$

$\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60$

We have to evaluate the probability that more than 47 cars carry just one person.

$P(x \geq 47)$

After continuity correction, we will evaluate

$P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)$

$= 1 - P(z \leq -2.6913)$

Calculation the value from standard normal z table, we have,

$P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%$

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0

3 years ago

ANSWER ALL FOR BRAINLIEST AND SHOW YOUR WORK

Black_prince [1.1K]

Answer:

Step-by-step explanation:

2. 11x + 5y - 6

3. - 97x -21y + 100

That's all i could do hope it helps :l

5 0

3 years ago