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Firdavs [7]
3 years ago
6

Work out the lowest common multiple of 42 and 63

Mathematics
2 answers:
Tomtit [17]3 years ago
4 0
The lowest common multiple, I think is 7?
Andru [333]3 years ago
3 0
7 would be your answer if im not mistaking 

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Please help!!!
sveticcg [70]

Answer:

I don't know how to do this thing

8 0
2 years ago
How much will it cost to pour a circular slab 18 ft in diameter by 3 in. For a patio if the concrete costs $40.00 per cubic yard
sasho [114]
A circular concrete slab is a cylinder. Vol = pi%2Ar%5E2%2Ah
in this cylinder:
r = 18%2F2 = 9 ft
h = 3%2F12 = .25 ft
:


Find the volume in cu/ft:
V = pi%2A9%5E2%2A.25
V = 63.61725 cu/ft
:
Change to cubic yds; (1 cu/yd = 27 cu/ft) and multiply by $40:
Cost = 63.61725%2F27 * 40
Cost = $94.25


In practical terms , they may require you to buy 3 cu/yds , which is $120


Yan na po
4 0
2 years ago
The recipe calls for 10 serving and I need 30 what number would I multiply
ivolga24 [154]

Answer:30

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Two siblings' ages have a sum of 64 years. The older sibling was born 6 years before their young sibling.
Elina [12.6K]

Hi!

So we have to make a system of equations here.

Let sibling 1 be O and sibling 2 be Y (for older and younger)

So:

O + Y = 64

O = 64 - Y

(Either one works)

The older sibling is 6 years older.

O = Y + 6

Make everything in terms of Y.

64 - Y = Y + 6

Same to both:

58 = 2y

2y = 58

Divide by 2 on both sides:

y = 29

Since the older sibling is 6 years older:

29 + 6 = 35

Y = 29

O = 35

Let me know if you have any questions.

4 0
2 years ago
If 1200 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the b
Colt1911 [192]

Answer:

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

Step-by-step explanation:

Given

Volume of a box = length × breadth × height= l×b×h

In this case the box have a square base. i.e l=b

Volume V = l^2 × h

The surface area of a square box

S = 2(lb+lh+bh)

S = 2(l^2 + lh + lh) since l=b

S = 2(l^2 + 2lh)

Given that the box is open top.

S = l^2 + 4lh

And Surface Area of the box is 1200cm^2

1200 = l^2 + 4lh ....1

Making h the subject of formula

h = (1200 - l^2)/4l .....2

Volume is given as

V = l^2 × h

V = l^2 ×(1200 - l^2)/4l

V = (1200l - l^3)/4

the maximum point is at dV/dl = 0

dV/dl = (1200 - 3l^2)/4

dV/dl = (1200 - 3l^2)/4 = 0

3l^2= 1200

l^2 = 1200/3 = 400

l = √400

I = 20cm

Since,

h = (1200 - l^2)/4l

h = (1200 - 20^2)/4×20

h = (800)/80

h = 10cm

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

4 0
3 years ago
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