4 years ago

Work out the lowest common multiple of 42 and 63

Mathematics

2 answers:

Tomtit [17]4 years ago

4 0

The lowest common multiple, I think is 7?

Andru [333]4 years ago

3 0

7 would be your answer if im not mistaking

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What's the solution of x+2/5= 12 ?

Feliz [49]

Answer:

11 3/5

Step-by-step explanation:

x+2/5=12

First, you subtract 2/5 from both sides, so the equation becomes:

x=11 3/5

Therefore, x equals 11 3/5

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3 years ago

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How to make ten to add

Oksana_A [137]

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3 years ago

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In this diagram, bac~edf. if the area of bac= 6 in.², what is the area of edf? PLZ HELP PLZ PLZ PLZ

Bad White [126]

Answer:

2.7 in²

Step-by-step explanation:

Since ∆BAC and ∆EDF are similar, therefore, the ratio of their area = square of the ratio of their corresponding side lengths.

Thus, if area of ∆EDF = x, area of ∆BAC = 6 in², EF = 2 in, BC = 3 in, therefore:

$\frac{6}{x} = (\frac{3}{2})^2$

$\frac{6}{x} = (1.5)^2$

$\frac{6}{x} = 2.25$

$\frac{6}{x}*x = 2.25*x$

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3 years ago

How do you solve problem G ???

yanalaym [24]

I think you add the exponents im not sure haven't done it in long time

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4 years ago

Find the 5th term of the sequence in which t1 = 8 and tn-1 = t= -3tn-1

il63 [147K]

I think you mean to say that the sequence is given recursively by

$\begin{cases}t_1=8\\t_n=-3t_{n-1}\end{cases}$

From this you can find a general pattern for the $n$ th term, but since we're only interested in determining $t_5$ , we can stop once we arrive at that. We have

$t_2=-3t_1$
$t_3=-3t_2=(-3)^2t_1$
$t_4=-3t_3=(-3)^3t_1$
$t_5=-3t_4=(-3)^4t_1$

$\implies t_5=8(-3)^4=8(81)=648$

7 0

3 years ago