Work out the lowest common multiple of 42 and 63
2 answers:
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Answer:
1)PT = 21 units
2)Option D
3)Option A
4)∠EFG = 2(24) +15 = 63 degrees
∠GFH= 4(24) +21 = 117 degrees
5) circumference = 21.98 cm
Step-by-step explanation:
1) As the T is midpoint, PT is equal to TQ in magnitude.
Thus,
x=5.
Thus, PT = 4(5) + 1 = 21
2) The planes XTS and VRS intersect in the line SW, and the intersection is perpendicular.
3)For a line to be defined, it must have 2 points, start and end.
The option A) is not defined properly, so incorrect
4)As the angles are linear pair, their sum is 180 degrees.
Thus,
n =
∠EFG = 2(24) +15 = 63 degrees
∠GFH= 4(24) +21 = 117 degrees
5) diameter = 7 cm
radius = 3.5 cm
circumference =
Answer:
5981.25 m²
Step-by-step explanation:
1. Divide the court into two sections. One section being the semicircle, the other being the rectangle.
2. Multiply 100 by 50 to get the area of the rectangle, which is 5000.
3. Divide 50 by 2 to get the radius of the semicircle, which is 25.
4. Find the formula used for area of a semicircle A = r²
5. Insert 25 into where the "r" is in the equation: A = (25²), resulting in about 981.25. (I replaced
with 3.14)
6. Add the area of the rectangle with the area of the semicircle, 5000 + 981.25 = 5981.25.
7. The final answer is 5981.25 m².