Wich expression is equivalent to (3x^5+8x^3)-(7x^2-6x^3)

What is the solution of the inequality Y+1<6

umka2103 [35]

Answer:

y < 5

Step-by-step explanation:

Given

y + 1 < 6 ( isolate y on the left side by subtracting 1 from both sides )

y < 5

6 0

3 years ago

Read 2 more answers

Please help brainliest<br> (Algebra 1)

den301095 [7]

Answer:

B - 11 > (w - 4)²

C - y < 3⁴

D - 5 + 9 < 5 · 9

are your correct answers

Step-by-step explanation:

x² - 5x + 6 and z + 11 / 2z - 1 are equalities phrases and rest of them will be inequalities.

HOPE THIS HELPS YOU

Follw me = 10 thanks

Mark as brainliest = 10 thanks

1 thanks to me = 2 thanks

3 0

2 years ago

Find the area of a regular hexagon with a 48- inch perimeter

solmaris [256]

First, you must find the side length. It is a hexagon so there are 6 sides. You take the perimeter by 6 48/6 and get 8. Then plug it into formula (3 sqrt 3)/2 a^2 where a is side length. Plug into formula and get an answer of 166.28 in^2

7 0

3 years ago

The realtor and her clients do not know the average home sale price for all of Guelph (500 was actually just a guess). However,

strojnjashka [21]

Answer:

a) The 99% confidence interval would be given by (346.708;453.292)

b) The 99% confidence interval would be given by (338.445;461.555)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=400$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=80$ represent the population standard deviation

n=15 represent the sample size

2) Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$400-2.58\frac{80}{\sqrt{15}}=346.708$

$400+2.58\frac{80}{\sqrt{15}}=453.292$

So on this case the 99% confidence interval would be given by (346.708;453.292)

3) Part b

For this case we don't know the population deviation so we need to use the t distribution instead the normal standard distribution.

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

We need to find the degrees of freedom first df=n-1=15-1=14

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that $t_{\alpha/2}=2.98$