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Rufina [12.5K]
3 years ago
5

5x+4y=14-2x-8y=20please show workanswer quickly

Mathematics
1 answer:
docker41 [41]3 years ago
5 0

Answer:

:work

Step-by-step explanation:

;c

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James is taking a test to be on a game show to win money. He has to answer 75 questions or more correctly in 3 rounds in order t
Tresset [83]

Answer:

Yes; James got 76 answers correct

Step-by-step explanation:

Round 1: 50 x 0.8 = 40

Round 2: 40 x 0.75 = 30

Round 3: 30 x 0.2 = 6

40 + 30 + 6 = 76

7 0
3 years ago
Given triangle MNP is isosceles and the two base angles are 6yº and (8y - 16)º. What is the measure of each base angle? (Hint: S
zvonat [6]
Two angles are equals.

Suppose they are 6y.

Then 6y + 6y + 8y - 16 = 180
20y = 180 +16
20y = 196
y = 9.8

Then one base angle is 6*9.8 = 58.8°

And the other base angle is 8(9.8) - 16 = 62.4.

Now suppose that the two equal angles are 8 y -16

Then 8y -1 6 + 8y - 16 + 6y = 180

Then 16y - 32 = 180

16y = 180 + 32
16y = 212
y = 13.25

One angle is 6(13.25) = 79.5

And the other is 8(13.25) - 16 = 90

This last solution is imposible.

So the answer is 58.8 and 62.4

 
7 0
4 years ago
2m/(2m 3)-(2m)/(2m-3)=1how many extraneous solutions does the equation have?
Slav-nsk [51]
\frac{2m}{2m+3} - \frac{2m}{2m-3} =1 \\  \frac{2m(2m-3)-2m(2m+3)}{4m^2-9} =1 \\  \frac{4m^2-6m-4m^2-6m}{4m^2-9} =1 \\  \frac{-12m}{4m^2-9} =1 \\ -12m=4m^2-9 \\ 4m^2+12m-9=0 \\ m=0.6213 \ or \ m=-3.6213
For m = 0.6213, \frac{2(0.6213)}{2(0.6213)+3} - \frac{2(0.6213)}{2(0.6213)-3} \\  \frac{1.2426}{4.2426} - \frac{1.2426}{-1.7574} =0.2929+0.7071=1
For m = -3.6213, \frac{2(-3.6213)}{2(-3.6213)+3} - \frac{2(-3.6213)}{2(-3.6213)-3} \\ \frac{-7.2426}{-4.2426} - \frac{-7.2426}{-10.2426} =1.7071-0.7071=1
Therefore, the equation has no extraneous solution.
4 0
3 years ago
Pls help me solve this questionnnnn
BigorU [14]

9514 1404 393

Answer:

  • arc BC = 60°
  • m∠ADC = 60°
  • m∠AEB = 105°
  • m∠ADP = 45°
  • m∠P = 60°

Step-by-step explanation:

The sum of arcs of a circle is 360°. The given conditions tell us arc BC ≅ arc AB, so the four arcs of the circle have ratios ...

  CB : BA : AD : DC = 2 : 2 : 3 : 5

The sum of ratio units is 2+2+3+5 = 12, so each one stands for 360°/12 = 30°. Then the arc lengths are ...

  arc BC = arc BA = 60° . . . . 2 ratio units each

  arc AD = 90° . . . . . . . . . . . . 3 ratio units

  arc DC = 150° . . . . . . . . . . . .5 ratio units

The inscribed angles are half the measure of the intercepted arcs:

  ∠ADC = (1/2) arc AC = 1/2(120°) = 60°

  ∠ADP = 1/2 arc AD = 1/2(90°) = 45°

The angles at E are half the sum of the measures of the intercepted arcs.

  ∠AEB = (arc AB + arc CD)/2 = (60° +150°)/2 = 105°

Angle P is half the difference of the intercepted arcs.

  ∠P = (arc BD -arc AD)/2 = (210° -90°)/2 = 120°/2 = 60°

__

In summary, ...

  arc BC = 60°

  m∠ADC = 60°

  m∠AEB = 105°

  m∠ADP = 45°

  m∠P = 60°

6 0
3 years ago
Which statement is true about the two triangles?
mote1985 [20]
C is the correct answer

4 0
4 years ago
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