Answer:
Yes; James got 76 answers correct
Step-by-step explanation:
Round 1: 50 x 0.8 = 40
Round 2: 40 x 0.75 = 30
Round 3: 30 x 0.2 = 6
40 + 30 + 6 = 76
Two angles are equals.
Suppose they are 6y.
Then 6y + 6y + 8y - 16 = 180
20y = 180 +16
20y = 196
y = 9.8
Then one base angle is 6*9.8 = 58.8°
And the other base angle is 8(9.8) - 16 = 62.4.
Now suppose that the two equal angles are 8 y -16
Then 8y -1 6 + 8y - 16 + 6y = 180
Then 16y - 32 = 180
16y = 180 + 32
16y = 212
y = 13.25
One angle is 6(13.25) = 79.5
And the other is 8(13.25) - 16 = 90
This last solution is imposible.
So the answer is 58.8 and 62.4

For m = 0.6213,

For m = -3.6213,

Therefore, the equation has no extraneous solution.
9514 1404 393
Answer:
- arc BC = 60°
- m∠ADC = 60°
- m∠AEB = 105°
- m∠ADP = 45°
- m∠P = 60°
Step-by-step explanation:
The sum of arcs of a circle is 360°. The given conditions tell us arc BC ≅ arc AB, so the four arcs of the circle have ratios ...
CB : BA : AD : DC = 2 : 2 : 3 : 5
The sum of ratio units is 2+2+3+5 = 12, so each one stands for 360°/12 = 30°. Then the arc lengths are ...
arc BC = arc BA = 60° . . . . 2 ratio units each
arc AD = 90° . . . . . . . . . . . . 3 ratio units
arc DC = 150° . . . . . . . . . . . .5 ratio units
The inscribed angles are half the measure of the intercepted arcs:
∠ADC = (1/2) arc AC = 1/2(120°) = 60°
∠ADP = 1/2 arc AD = 1/2(90°) = 45°
The angles at E are half the sum of the measures of the intercepted arcs.
∠AEB = (arc AB + arc CD)/2 = (60° +150°)/2 = 105°
Angle P is half the difference of the intercepted arcs.
∠P = (arc BD -arc AD)/2 = (210° -90°)/2 = 120°/2 = 60°
__
In summary, ...
arc BC = 60°
m∠ADC = 60°
m∠AEB = 105°
m∠ADP = 45°
m∠P = 60°