Hi there! The formula for simple interest is prt. That means multiply the principal (initial amount) by the rate (simple interest rate) by the time (could be in months or years). In this case, we multiply 475 * 5% (0.05) to get 23.75. That's $23.75 in interest each year, but we're looking for the amount earned in 10 years. To do this, multiply 23.75 by 10. When you do, you get 237.5. There. $237.50 in interest will be earned in 10 years.
Answer:
2z + 5
Step-by-step explanation:
you have to combine like terms
subtract 4z - 2z and you get 2z
the number with the variable next to it goes first not the constant
2z + 5
the variable is z and the constant is 5 because it doesn't have variable next to it
hope this makes sense and helps :)
tell me if you have any questions
You could do 37+230 or 40 + 235
Short AnswerThere are two numbers
x1 = -0.25 + 0.9682i <<<<
answer 1x2 = - 0.25 - 0.9582i <<<<
answer 2 I take it there are two such numbers.
Let one number = x
Let one number = y
x + y = -0.5
y = - 0.5 - x (1)
xy = 1 (2)
Put equation 1 into equation 2
xy = 1
x(-0.5 - x) = 1
-0.5x - x^2 = 1 Subtract 1 from both sides.
-0.5x - x^2 - 1 = 0 Order these by powers
-x^2 - 0.5x -1 = 0 Multiply though by - 1
x^2 + 0.5x + 1 = 0 Use the quadratic formula to solve this.

a = 1
b = 0.5
c = 1

x = [-0.5 +/- sqrt(0.25 - 4)] / 2
x = [-0.5 +/- sqrt(-3.75)] / 2
x = [-0.25 +/- 0.9682i
x1 = -0.25 + 0.9682 i
x2 = -0.25 - 0.9682 i
These two are conjugates. They will add as x1 + x2 = -0.25 - 0.25 = - 0.50.
The complex parts cancel out. Getting them to multiply to 1 will be a little more difficult. I'll do that under the check.
Check(-0.25 - 0.9682i)(-0.25 + 0.9682i)
Use FOIL
F:-0.25 * -0.25 = 0.0625
O: -0.25*0.9682i
I: +0.25*0.9682i
L: -0.9682i*0.9682i = - 0.9375 i^2 = 0.9375
NoticeThe two middle terms (labled "O" and "I" ) cancel out. They are of opposite signs.
The final result is 0.9375 and 0.0625 add up to 1
Answer:
The correct answer is True.
Step-by-step explanation:
Altitude: vertical distance either between the top and bottom of something or between a base and something above it.